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evablogger [386]
3 years ago
12

Part A Determine the magnitude of the x component of F using scalar notation. Fx F x = nothing lb Request Answer Part B Determin

e the magnitude of the y component of F using scalar notation. Fy F y = nothing lb Request Answer Part C Determine the magnitude of the z component of F using scalar notation. Fz F z = nothing lb Request Answer Provide Feedback Figure1 of 1A force vector acting on a ring attached to the ground is shown in the xyz space together with its x, y, and z components lying on the corresponding positive axes. The ring is located at the origin. Force F is located in the first octant. F makes an angle of 60 degrees with its x component and an angle of 45 degrees with its y component. A force vector acting on a ring attached to the ground is shown in the xyz space together with its x, y, and z components lying on the corresponding positive axes. The ring is located at the origin. Force F is located in the first octant. F makes an angle of 60 degrees with its x component and an angle of 45 degrees with its y component.
Physics
1 answer:
maksim [4K]3 years ago
5 0

As we know that force F makes an angle of 60 degree with X axis

so the X component is given as

cos60 = \frac{F_x}{F}

now we have

F_x = F cos60

F_x = 0.50 F

Similarly we know that force F makes an angle of 45 degree with Y axis

so the X component is given as

cos45 = \frac{F_y}{F}

now we have

F_y = F cos45

F_y = 0.707 F

Now for the component along z axis we know that

F_x^2 + F_y^2 + F_z^2 = F^2

now plug in all components

(0.707 F)^2 + (0.50 F)^2 + F_z^2 = F^2

0.5 F^2 + 0.25 F^2 + F_z^2 = F^2

F_z^2 = F^2(1 - 0.75)

F_z^2 = 0.25 F^2

F_z = 0.5 F

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4 years ago
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Zina [86]

Answer:

The value of spring constant is 266.01 \frac{N}{m}

Explanation:

Given:

Mass of pellet m = 2.01 \times 10^{-2} kg

Height difference of pellet rise h_{f} - h_{o} = 6.03 m

Spring compression x = 9.45 \times 10^{-2} m

From energy conservation law,

Spring potential energy is stored into potential energy,

  mg(h_{f} -h_{o})  = \frac{1}{2} kx^{2}

Where k = spring constant, g = 9.8 \frac{m}{s^{2} }

  k = \frac{2mg(h_{f} -h_{o} )}{x^{2} }

  k = \frac{2 \times 9.8 \times 6.03\times 2.01 \times 10^{-2} }{(9.45\times 10^{-2} )^{2} }

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Therefore, the value of spring constant is 266.01 \frac{N}{m}

6 0
3 years ago
The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.4cm apart with a 28kV potential d
yulyashka [42]

Answer:

a)   F = 3.2 10⁻¹⁰ N , b)       v = 9.9 10⁷ m / s

Explanation:

a) The electric force is

       F = q E

The electric field is related to the potential reference

     V = E d

     E = V / d

Let's replace

    F = e V / d

Let's calculate

    F = 1.6 10⁻¹⁹ 28 10³ / 1.4 10⁻²

    F = 3.2 10⁻¹⁰ N

b) For this part we can use kinematics

          v² = v₀ + 2 a d

          v = √ 2 ad

Acceleration can be found with Newton's second law

        e V / d = m a

        a = e / m V / d

        a = 1.6 10⁻¹⁹ / 9.1 10⁻³¹ 28 10³ / 1.4 10⁻²

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Let's calculate the speed

       v = √ (2 3,516 10¹⁷ 1.4 10⁻²)

       v = √ (98,448 10¹⁴)

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3 0
3 years ago
A pair of slits separated by 1 mm, are illuminated with monochromatic light of wavelength 411 nm. The light falls on a screen 1.
Ilya [14]

Answer:

t = 0.192 \mu m

Explanation:

Path difference due to a transparent slab is given as

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here we know that

\mu = 1.79

now total shift in the bright fringe is given as

Shift = \frac{D(\mu - 1)t}{d}

Also we know that the fringe width of maximum intensity is given as

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\frac{D}{d} = \frac{\delta x}{\lambda}

now the shift is given as

Shift = \frac{(\mu - 1) t \delta x}{\lambda}

given that the shift is

Shift = 0.37 \delta x

here we have

0.37 \delta x = \frac{(\mu - 1) t \delta x}{\lambda}

now plug in all values in it

0.37 = \frac{(1.79 - 1) t}{411 \times 10^{-9}}

t = 0.192 \times 10^{-6} m

t = 0.192 \mu m

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Answer:Tyrone is 12 more kg more than Ella.

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7 0
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