the reagents necessary to convert alcohol to ketone
which involves oxidation of alcohols.
<h3>
What is oxidation of alcohols?</h3>
- Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
- In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
- In order to cause primary alcohols to oxidize into aldehydes
(dichromate)
/pyridine (Collins reagent)- Chromium pyridinium compound (PCC)
- Dichromate of pyridinium (PDC, Cornforth reagent)
- Periodinane by Dess-Martin
- Oxalyl chloride with dimethylsulfoxide (DMSO) for Swern
- oxidation of secondary alcohols to ketones
- (dichromate)
- /pyridine (Collins reagent)
- Chromium pyridinium compound (PCC)
- Dichromate of pyridinium (PDC, Cornforth reagent)
- Periodinane by Dess-Martin
- Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
/acetone (Jones oxidation)- Acetone with aluminum isopropoxide (Oppenauer oxidation)
To learn more about oxidation of alcohols with the given link
brainly.com/question/7207863
#SPJ4
<u>Question:</u>
Identify the reagents necessary to achieve each of the following transformations
Answer:
The number of lines possible for SO2 is 3
Explanation:
The following Procedure should be followed when calculating the number of vibrational modes:-
- Identify if the given molecule is either linear or non-linear
- Calculate the number of atoms present in your molecule
- Place the value of n in the formula and solve.
SO2 is a non-linear molecule because it contains a lone pair which causes the molecule to bent in shape hence, The mathematical formula for calculating the number of non-linear molecule in a infrared region is (3n - 6) here n is the number of atoms in molecule.
hence for Sulphur Dioxide (SO2), n will be 3
<u> Therefore, The number of lines possible for SO2 is (3*3) - 6 = 3</u>
Answer:
The answer is
<h2>250 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of object = 25 mL
Density = 10 g/mL
The mass of the object is
mass = 25 × 10
We have the final answer as
<h3>250 g</h3>
Hope this helps you
0.953948 is what I got from dividing pressure value by 760.
So let's use some equations to represent the data [let R= cost of ring & B= cost of bracelet]
R= B + $ 36 .... (1)
B=
× R ... (2)
By using simultaneous equations to solve for B and R.
Substitute eq. (1) into eq. (2)
B =
× (B + $36)
B =
B +
⇒ B = $48
By substituting value of B into ea (1)
If R = B + $36
R = ($48) + $36
= $84
∴ <span> the total of the two items = R + B
= $84 + $48
</span> = $132
