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Ulleksa [173]
3 years ago
15

Physical properties of Ammonium Sulphate

Chemistry
1 answer:
Sliva [168]3 years ago
6 0

the physical properties of ammonium  sulphate are colorless gas, less dense than air, pungent shell, very soluble in water, alkaline gas

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UHHH helpppp maya cause uh she d.a.n.g d.u.m.b.
inna [77]

Answer:

17

Explanation:

the mass number of the element which is protons and neutrons is 17+18=35

electronic configuration is 2, 8, 7

valency of the element is 1 therefore the atomic number is 17

6 0
3 years ago
Read 2 more answers
Which element is best known for it's bad smell?
tia_tia [17]
The bad smelling element is Sulfur, which smells like rotting eggs.
5 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is
Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0
3 years ago
Sắp xếp các hợp chất: HF, HI, HBr, HCl theo chiều giảm dần tính axit.
mixer [17]
I don’t know what to answer
6 0
2 years ago
What does a balanced equation allows you to determine
Allushta [10]

It allows you to determine the relation between the reactants and the products.

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3 years ago
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