Answer:
We need 75 mL of 0.1 M NaOH ( Option C)
Explanation:
<u>Step 1: </u>Data given
Molarity of NaOH solution = 0.100 M
volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L
<u>Step 2:</u> The balanced equation
CH3COOH + NaOH → CH3COONa + H2O
<u>Step 3:</u> Calculate moles of CH3COOH
Moles CH3COOH = Molarity * volume
Moles CH3COOH = 0.150 M * 0.05 L
Moles CH3COOH = 0.0075 moles
<u>Step 4</u>: Calculate moles of NaOH
For 1 mol of CH3COOH we need 1 mol of NaOH
For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH
<u>Step 5:</u> Calculate volume of NaOH
volume = moles / molarity
volume = 0.0075 moles / 0.100 M
Volume = 0.075 L = 75 mL
We need 75 mL of 0.1 M NaOH
