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sukhopar [10]
3 years ago
7

All charged objects create an electric field around them. What two factors determine the strength of two electric fields upon th

e charged objects creating them?
Physics
1 answer:
V125BC [204]3 years ago
3 0
-- The product of the magnitudes of the two charges.
-- The distance between the centers of the two charges.

The signs of the charges ... whether their signs are the same
or opposite ... determines the direction of the forces, but not
their magnitude.
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Answer:

the fraction of submerged volume is equal to the ratio of the densities of the body between the density of the fluid.

Explanation:

This is a fluid mechanics problem, where as the boat is in equilibrium with the pushing force we can write Newton's second law

                  B- W = 0

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the thrust force is equal to the weight of the liquid that is dislodged

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we substitute

             ρ g V = m g

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we can write the mass of the pot as a function of its density

             ρ_body = m / V_body

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             V_fluid / V_body = ρ_body / ρ _fluid         2

Equations 1 and 2 are similar, although 2 is easier to analyze, the fraction of submerged volume is equal to the ratio of the densities of the body between the density of the fluid.

The effect appears the pot as if it had a lower apparent weight

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Answer:

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Answer:

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