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sveta [45]
3 years ago
7

A. What does the identity of an element depend on the number of? B. electrons in the atom C. neutrons in the atom D. protons and

neutrons in the nucleus E. protons in the atom
Chemistry
2 answers:
Deffense [45]3 years ago
8 0

Answer:

protons in the atom      just took the test

antiseptic1488 [7]3 years ago
6 0

Answer:

B

Explanation:

i hope this help but if it didn't tell me.

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Assume that 8.5 L of iodine gas (I2) are produced at STP according to the following balanced equation:2KI(aq) + Cl2(
Aliun [14]

Answer: 0.3794 moles of Iodine gas are produced.

Explanation:

2KI(aq)+Cl_2(
g)\rightarrow 2KCl(aq)+I_2

Volume of iodine gas produced at STP =8.5 L

At STP, the 1 mol of gas occupies volume = 22.4 L

So, 8.5 L of volume will be occupied by:\frac{1}{22.4 L}\times 8.5=0.3794 moles

0.3794 moles of Iodine gas are produced.

5 0
3 years ago
Read 2 more answers
Name the following aromatic hydrocarbon:
Tresset [83]

3-Methylpentane is the IUPAC name for the substance.

whether in a continuous chain or a ring, the longest chain of carbons joined by a single bond serves as the basis for IUPAC nomenclature. According to a precise set of priorities, all deviations—whether they involve numerous bonds or atoms other than carbon and hydrogen—are denoted by prefixes or suffixes.

+3-Methylpentane is the IUPAC name for the substance in question. It has a lengthy chain of 5 carbon atoms, which gives it the prefix pent-, and a single bond is what gives it the postfix -ane (alkane). Given that the methyl group is present at the third carbon, it is 3-methylpentane.

Learn more about IUPAC Nomenclature here-

brainly.com/question/14379357

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8 0
2 years ago
I could really use some help with this question, thank you in advance!​
Taya2010 [7]
C because
Explanation Plato
6 0
2 years ago
Nickel (iii) cyanide + aluminum permanganate product?
Wewaii [24]

Answer:

Nickel(II) cyanide is an inorganic compound with a chemical formula Ni(CN)₂

Explanation:

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5 0
3 years ago
When excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass o
irakobra [83]

The mass of sodium sulfite that was used will be 1,890 grams.

<h3>Stoichiometric problems</h3>

First, the equation of the reaction:

NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2

The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.

Mole of 960 grams SO2 = 960/64 = 15 moles

Equivalent mole of sodium sulfite that reacted = 15 moles

Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams

More on stoichiometric problems can be found here: brainly.com/question/14465605

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1 year ago
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