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lubasha [3.4K]
3 years ago
8

Write the following in scientific notation. Include the unit or it will be marked wrong. a. 3450 meters b. 0.0000432 liters c. 5

060000 cm^3
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

a. \: 3.450 \:  \times  \:  {10}^{3} \:  m \\  \\ b. \: 4.32 \:  \:  \times  \:  {10}^{ - 5}  \: l \\  \\ c. \: 5.06 \:  \times  \:  {10}^{5}  {cm}^{3}

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Having the same number of valence electrons means having similar chemical properties.
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Answer:

True

Explanation:

Because atoms with the same number of valence electrons react in similar ways with other elements.

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65.9% Ba and 34.1% CI
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What was the question?
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3 years ago
What is the overall enthalpy of reaction for the equation shown below?
Rudiy27

Answer:

ΔH₁₂ = -867.2 Kj

Explanation:

Find enthalpy for 3H₂ + O₃ => 3H₂O given ...

2H₂ + O₂ => 2H₂O      ΔH₁ = -483.6 Kj

        3O₂ => 2O₃        ΔH₂ = + 284.6 Kj

_____________________________

3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O       (multiply by 3 to cancel O₂)

6H₂ + 3O₂ => 6H₂O        ΔH₁ = 3(-483.6 Kj) = -1450.6Kj

          2O₃ => 3O₂           ΔH₂ = -284.6Kj              (reverse rxn to cancel O₂)

_______________________________

6H₂ + 2O₃ => 6H₂O         ΔH₁₂ = -1735.2 Kj       (Net Reaction - not reduced)

________________________________

divide by 2 => target equation (Net Reaction - reduced)

3H₂ + O₃ => 3H₂O            ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj    

4 0
3 years ago
Democritus thought that matter was made of tiny particles
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that were all round and smooth

6 0
3 years ago
The decomposition of potassium chlorate into kcl & o2 is used as a source of oxygen in the laboratory. How many moles of pot
fredd [130]

Answer:

10moles of kcl

Explanation:

2 K C l O3 →  2 K C l  +  3 O 2

Notice that you have a  2 : 3  mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you'll always produce 2/3 times more moles of the latter.

15 mol of O2 * ((2mol of KCLO3)/(3mol of O2))= 15*2/3=10 Mol

5 0
4 years ago
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