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timofeeve [1]
3 years ago
6

A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply force A, as part

Physics
1 answer:
aniked [119]3 years ago
4 0

Answer:

The ratio is 1:1

Explanation:

Firstly we are told the in (a) we have a force which A given to be: FA

We are then told the are two other forces which a B and C which are equal.

These forces are given to be F and 19.5° away from A.

We are then told that the force on the elephant is now three times, of what it was when we only had force A.

Since we are told that B and C are eqaula.

If we say FA = 2N

Then in order for it to be three times, we would have to add 4N since it was the only force present at the time.

If we add two equal forces, then we can devide that 4 by 2.

We then find out that F =2N

and thus equal to FA.

Therefore the ratio of F/FA is

!:1

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Un cuerpo se encuentra en reposo sobre una mesa horizontal. Entonces se puede afirmar que:
vazorg [7]

Answer:

C) solo III

Explanation:

Para solucionar este problema debemos analizar cada una de las opciones hasta llegar a la opcion valida.

I) el cuerpo pesa igual que su masa.

Esta opcion no puede ser ya que el peso de un cuerpo se define como el producto de la masa por la aceleracion gravitacion.

w=m*g

donde:

w = peso [N]

m = masa [kg]

g = aceleracion gravitacional = 9.81 [m/s²]

Como podemos ver el peso siempre sera mayar que la masa, ya que el peso es resultado de la multiplicacion de la masa por la gravedad.

II) Por medio de un analisis de fuerzas en el eje-y, la fuerza del peso se dirige hacia abajo mientras que la fuerza normal tiene igual magnitud, pero se dirige hacia arriba. Por esto la segunda opcion no puede ser.

III) El cuerpo se encuentra en equilibrio, es decir las unicas fuerzas que actuan sobre el cuerpo son el peso y la fuerza normal. Pero estas fuerzas son iguales y opuestas en direccion, por la tanto se cancelan y estan en equilibrio.

Esta es la opcion valida, la fuerza neta es nula.

5 0
3 years ago
Answer me nowwwwwwww
qwelly [4]

Answer:

volume

Explanation:

it depends on the volume of the items

hope this helps

8 0
3 years ago
Read 2 more answers
Somebody please help me my grade depends on it
Darya [45]

Answer:  Hope this helps!

Explanation:

a rock formed from particles that are deposited and lithified are sedimentary.

rocks formed from cooling and hardening magma or lava is igneous.

a rock formed when an already existing rock is subjected to extreme heat and pressure is metamorphic.

8 0
3 years ago
A woman lifts her 100-newton child up one meter and carries her for a distance of 50 meters to the 3.2
lianna [129]
(100 N) x (1 m) =<span>= 100 J

 hope that helps</span>
4 0
4 years ago
A 1.40-kg block is on a frictionless, 30 ∘ inclined plane. The block is attached to a spring (k = 40.0 N/m ) that is fixed to a
Oliga [24]

Answer:

the mass drop by 6.5cm before coming to rest.

Explanation:

Given that:

the mass of the block M= 1.40 kg

angle of inclination θ = 30°

spring constant K = 40.0 N/m

mass of the suspended block m = 60.0 g = 0.06 kg

initial downward speed = 1.40 m/s

The objective is to determine how far does it drop before coming to rest?

Let assume it drops at y from a certain point in the vertical direction;

Then :

Workdone by gravity on the mass of the block is:

w_1g = 1.4*9.81*y*sin30 = - 6.867y

Workdone by gravity on the mass of the suspended block is:

w_2g = 0.06*9.81 = 0.5886

The workdone by the spring = -1/2ky²

= -0.5 × 40y²

= -20 y²

The net workdone is = -20 y² - 6.867y + 0.5886y

According to the work energy theorem

Net work done = Δ K.E

-20 y² - 6.867y + 0.5886 = 1/2 × 0.06 × 1.4²

-20 y²  - 6.867y + 0.5886 = 0.5 × 0.1176

-20 y²  - 6.867y + 0.5886 = 0.0588

-20 y²  - 6.867y + 0.5886 - 0.0588

-20 y²  - 6.867y + 0.5298 = 0

multiplying through by (-)

20 y²  + 6.867y - 0.5298 = 0

Using the quadratic formula:

\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}

where;

a = 20 ; b = 6.867 c= - 0.5298

\dfrac{-(6.867)  \pm \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)}

= \dfrac{-(6.867)  + \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)} \ \ \ OR \ \ \  \dfrac{-(6.867)  - \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)}= 0.0649 OR  −0.408

We go by the positive integer

y = 0.0649 m

y = 6.5 cm

Therefore; the mass drop by 6.5cm before coming to rest.

7 0
4 years ago
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