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3 years ago

A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply force A, as part

Physics

1 answer:

aniked [119]3 years ago

4 0

Answer:

The ratio is 1:1

Explanation:

Firstly we are told the in (a) we have a force which A given to be: FA

We are then told the are two other forces which a B and C which are equal.

These forces are given to be F and 19.5° away from A.

We are then told that the force on the elephant is now three times, of what it was when we only had force A.

Since we are told that B and C are eqaula.

If we say FA = 2N

Then in order for it to be three times, we would have to add 4N since it was the only force present at the time.

If we add two equal forces, then we can devide that 4 by 2.

We then find out that F =2N

and thus equal to FA.

Therefore the ratio of F/FA is

!:1

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A meteoroid is moving towards a planet. It has mass m = 0.78×109 kg and speed v1 = 4.1×107 m/s at distance R1 = 2.8×107 m from t

wariber [46]

Answer:

$PE=81.755\, J$

Explanation:

Given that:

mass of meteoroid, $m=7.8\times 10^8 \,kg$

radial distance from the center of the planet, $R= 2.8\times 10^7 m$

mass of the planet, $M=4.4\times 10^{25}\, kg$

<u>For gravitational potential energy we have:</u>

$PE=G\frac{M.m}{R}$

substituting the respective values:

$PE=6.67\times 10^{-11}\times \frac{4.4\times 10^{25}\times 7.8\times 10^8}{2.8\times 10^7}$

$PE=81.755\, J$

5 0

3 years ago

Which items are matter?

Mumz [18]

Without being provided a list of items, I would have to generally say that everything around you is matter. There are a few exceptions to this list, but a general rule of thumb is anything you can touch, taste, smell or hold would be considered matter. Sound, light, time (Dr. Who may disagree) and heat would be considered non-matter items.

3 0

3 years ago

A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3.0 m is initially at rest. A 20 kg boy approaches the m

nekit [7.7K]

Answer:

The velocity of the merry-go-round after the boy hops on the merry-go-round is 1.5 m/s

Explanation:

The rotational inertia of the merry-go-round = 600 kg·m²

The radius of the merry-go-round = 3.0 m

The mass of the boy = 20 kg

The speed with which the boy approaches the merry-go-round = 5.0 m/s

$F_T \cdot r = I \cdot \alpha = m \cdot r^2 \cdot \alpha$

Where;

$F_T$ = The tangential force

I = The rotational inertia

m = The mass

α = The angular acceleration

r = The radius of the merry-go-round

For the merry go round, we have;

$I_m \cdot \alpha_m = I_m \cdot \dfrac{v_m}{r \cdot t}$

$I_m$ = The rotational inertia of the merry-go-round

$\alpha _m$ = The angular acceleration of the merry-go-round

$v _m$ = The linear velocity of the merry-go-round

t = The time of motion

For the boy, we have;

$I_b \cdot \alpha_b = m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t}$

Where;

$I_b$ = The rotational inertia of the boy

$\alpha _b$ = The angular acceleration of the boy

$v _b$ = The linear velocity of the boy

t = The time of motion

When the boy jumps on the merry-go-round, we have;

$I_m \cdot \dfrac{v_m}{r \cdot t} = m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t}$

Which gives;

$v_m = \dfrac{m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t} \cdot r \cdot t}{I_m} = \dfrac{m_b \cdot r^2 \cdot v_b}{I_m}$

From which we have;

$v_m = \dfrac{20 \times 3^2 \times 5}{600} = 1.5$

The velocity of the merry-go-round, $v_m$ , after the boy hops on the merry-go-round = 1.5 m/s.

5 0

2 years ago

How do the prefixes micro,<br> nano and pico relate to each<br> other?

In-s [12.5K]

Answer:

because they are same and their properties

8 0

3 years ago

as the bright sun shines upon the water, the water slowly disappears . the same sunlight gives energy to the surrounding plants

Nata [24]

As the bright sun shines upon the water, the water slowly dissapears. This is an example of physical change because here the water is just transformed into water vapour. So only the state and the shape of the substance has changed. Its originality remains absolutely intact. In the second case where the same sunlight gives energy to the surrounding plants to convert water and carbon dioxide into sugar and oxygen gas, it is a chemical change. here new substances are formed and the identity of the original substances are lost.In chemical reactions, the mass of the product will always be the same as the mass of the reactants.

8 0

3 years ago