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2 years ago

A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply force A, as part

Physics

1 answer:

aniked [119]2 years ago

4 0

Answer:

The ratio is 1:1

Explanation:

Firstly we are told the in (a) we have a force which A given to be: FA

We are then told the are two other forces which a B and C which are equal.

These forces are given to be F and 19.5° away from A.

We are then told that the force on the elephant is now three times, of what it was when we only had force A.

Since we are told that B and C are eqaula.

If we say FA = 2N

Then in order for it to be three times, we would have to add 4N since it was the only force present at the time.

If we add two equal forces, then we can devide that 4 by 2.

We then find out that F =2N

and thus equal to FA.

Therefore the ratio of F/FA is

!:1

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A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision

Nimfa-mama [501]

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Δ KE = 249158.6 kJ

Explanation:

given data

Truck mass M = 1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum that is express as

Mu = (M+m) V .......................1

put here value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy will be here

Δ KE = $\frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2$ .................2

put here value and we get

Δ KE = $\frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2$

solve it we get

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2 years ago

A stone is dropped into a well. The sound of the splash is heard 6.25 s later. What is the depth of the well? (Take the speed of

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Answer:

depth of well is 163.30 m

Explanation:

Given data

speed of sound = 343 m/s

timer = 6.25 s

to find out

depth of well

solution

let us consider depth d

so equation will be

depth = 1/2 ×g ×t² ..............1

and

depth = velocity of sound × time .................2

here we have given time 6.25 that is sum of 2 time

when stone reach at bottom that time

another is sound reach us after stone strike on bottom

so time 1 + time 2 = 6.25 s

so from equation 1 and 2 we get

1/2 ×g ×t² = velocity of sound × time

1/2 ×9.8 × t1² = 343 × (6.25 - t1 )

t1 = 5.77376 sec

so height = 1/2 ×g ×t²

height = 1/2 ×9.8 × (5.773)²

height = 163.30 m

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3 years ago