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WITCHER [35]
3 years ago
12

3. What is the charge on the leaves of an electroscope if a positively charged rod is moved near the

Physics
1 answer:
dsp733 years ago
7 0
I believe the answer is letter B
You might be interested in
10x2poooop11111111qq64
yulyashka [42]

Answer:

10×2=20

10×2÷64=??

I am not sure what you are trying to say...

7 0
2 years ago
Read 2 more answers
1. How much energy is needed just to melt 0.56kg of ice at 0◦ C?
ivann1987 [24]

Answer:

This will require 266.9 of heat energy.

Explanation:

To calculate the energy required to raise the temperature of any given substance, here's what you require:The mass of the material, m The temperature change that occurs,  ΔT The specific heat capacity of the material,

c

(which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.

Here is a source of values of

c for different substances:

Once you have all that, this is the equation:

Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.)For water, the value of c is 4.186g°C So, Q=750×4.186×85=266=858=266.858

5 0
2 years ago
What determines how soon one action potential can follow another?
belka [17]
It is through biopsychological feedback. 

A class of chemical called a neurotransmitter is important in the transmission of nerve impulses. Neurotransmitters are packaged by the cell into small, membrane-bound sacs called vesicles. Upon receiving a chemical signal, the vesicles move toward the cell membrane and fuse with it, releasing the enclosed neurotransmitters from the terminal end of the nerve cell. 
5 0
3 years ago
A 72.0 kg stuntman jumps from a moving car to a 2.50 kg skateboard at rest. If the velocity of the car is 15.0 m/s to the east w
yawa3891 [41]

Answer:

B 14.5 m/s to the east

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, if the system is isolated, the total momentum of the system must be conserved.

Here the total momentum before the stuntman reaches the skateboard is:

p_i = Mv

where

M = 72.0 kg is the mass of the stuntman

v = 15.0 m/s is his initial velocity (to the east)

The total momentum after the stuntmen reaches the skateboard is:

p_f = (M+m)v'

where

m = 2.50 kg is the mass of the skateboard

v' is the final velocity of the stuntman and the skateboard

Since momentum must be conserved, we have

p_i = p_f\\Mv=(M+m)v'

And solvign for v',

v'=\frac{Mv}{M+m}=\frac{(72.0)(15.0)}{(72.0+2.50)}=14.5 m/s

And since the sign is the same as v, the direction is the same (to the east).

7 0
3 years ago
While playing football, Chris runs 4.5 m at 20⁰ south of west. If an opponent was trying to tackle him how far west and south wo
rewona [7]

Answer:

South = 1.5m

West =4.2m

Explanation:

Kindly see attached a rough draft of the situation

Step one

Given data

From the sketch the direction of the player is along the resultant of the triangle, corresponding to the Hypotenuse

Step two:

Hence for an opponent to tackle him towards the south, he must be at

sin θ= opp/hyp

sin 20=x/4.5

x=sin 20*4.5

x=0.342*4.5

x= 1.5m

Also, for an opponent to tackle him towards the south, he must be at

cos θ= adj/hyp

cos 20=y/4.5

y=cos 20*4.5

y=0.93*4.5

y= 4.2m

5 0
3 years ago
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