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WITCHER [35]
3 years ago
12

3. What is the charge on the leaves of an electroscope if a positively charged rod is moved near the

Physics
1 answer:
dsp733 years ago
7 0
I believe the answer is letter B
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A box is held at rest by two ropes that form 30° angles with the vertical. The tension T in either rope is 42 N. What is the wei
iragen [17]
<h3><u>Answer;</u></h3>

= 73 N

<h3><u>Explanation</u>;</h3>

Using the formula

2 T cos(30°) = w

Where; T is the tension on each string, while w is the weight of the box given by mg

Therefore;

W = 2Tcos 30°

    = 2 × 42 cos 30°

    = 84 cos 30°

    = 72.74

<u>   ≈ 73 N</u>

7 0
3 years ago
Q 36 - URGENT HELP PLS<br> WILL BE MARKED AS BRAINLIEST.
Sliva [168]
The answer is B.

This is because you add up all of the times (1.44s+1.70s+1.58s+1.76s) and you get 6.48 then you divide 6.48 by 4 to get the average of the times. Now you get the distance (200m) and because speed=distance/time you divide 200m/1.62s to get 123m/s. I hope this made sense :)
5 0
2 years ago
Which of the following statements is true of chords? Select all that apply.
tankabanditka [31]
All of those are true, except the one about the radius. 

Both ends of a chord have to be on the circle, but one end
of a radius is at the center, so a radius can't be a chord.
5 0
2 years ago
what did classical physics predict would happen to the light given of by an object as its tempurtare increased
alexgriva [62]
When the temperature of an object that is giving off light is increased, the particles in the object will move at a faster rate and there will be increased vibration of these molecules. This will makes the object to emit more light and to shine more brightly.
7 0
2 years ago
Read 2 more answers
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
IRISSAK [1]

To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,

F= \frac{\mu_0}{2\pi} \frac{I^2L}{d}

Here,

\mu_0 = Permeability free space

I = Current

L = Length

d= Distance between them

Our values are,

L = 0.67m

m = 0.082kg

d = 7.4*10^{-3}m

I = \text{Current through each of the wires}

Rearranging the previous equation to find the current,

\frac{mg}{L} = 2*10^{-7} (\frac{I^2}{d})

I = \sqrt{\frac{mgd}{(2*10^{-7})L}}

I = \sqrt{\frac{(0.082)(9.8)(7.4*10^{-3})}{(2*10^{-7})(0.67)}}

I = \sqrt{44377.9}

I = 210.66A

Therefore the current in the rods is 210.6A

8 0
3 years ago
Read 2 more answers
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