From reliable sources in the internet, the half-live of carbon-14 is given to be 5,730 years. In a span of 10,000 to 12,000 years, there are almost or little more than 2 half-lives. Thus, there should be
A(t) = A(0)(1/2)^t
where t is the number of half-lives, in this case 2. Thus, only about 1/4 of the original amount will be left.
Answer:
Explanation:
When a camera shifts focus from a faraway object to a nearby object, the lens-to-film distance must increase. Likewise, when it shifts focus from a nearby object to a distant object, there must be an increase in the lens to film distance (that is, the image distance).
Therefore, if the picture of an object that is far away, the lens must move towards the film.
The focal length cannot be changed because it is fixed for a lens. Nevertheless, in order to focus on an object, the image distance can be changed.
Answer:
T = 6.0 N
Explanation:
given,
mass of the cord = 0.46 Kg
length of the supports = 7.2 m
time taken to travel = 0.74 s
tension in the chord = ?
using formula for tension calculation
![T = \dfrac{v^2.m}{l}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7Bv%5E2.m%7D%7Bl%7D)
![v = \dfrac{l}{s}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7Bl%7D%7Bs%7D)
![v = \dfrac{7.2}{0.74}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B7.2%7D%7B0.74%7D)
v = 9.73 m/s
now, calculation of tension
![T = \dfrac{9.73^2\times 0.46}{7.2}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B9.73%5E2%5Ctimes%200.46%7D%7B7.2%7D)
T = 6.0 N
The tension in the cord is equal to 6.0 N.
Answer:
2700
Explanation:
because calculate the minute1=60×45=2700