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andreev551 [17]
3 years ago
15

Is your increase in gravitational potential energy the same in both cases? When Climbing a mountain on a zigzag path and on a st

raight path
Physics
1 answer:
baherus [9]3 years ago
7 0

Answer:

The increase in gravitational potential energy is the same in both cases

Explanation:

It is easier to climb a mountain in a zigzag way rather than climbing on a straight line but since the distance is the same ( vertical height ) , mass and gravity is the same. Hence the increase in gravitational potential energy is the same in both cases.

gravitational potential energy = mgh ( same in both cases )

m = mass

g = acceleration due to gravity

h = distance ( vertical height )

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The difference between experimental technique and procedure
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A procedure is all the steps used to do an experiment in order. 
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<span>the procedure is all the steps of the experiment.</span>
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4 years ago
How can you increase the gravitational potential energy (GPE) of an empty shoe box on the bottom shelf of a bookcase
Anettt [7]

Answer:

Add items to the box

Explanation: I did the test

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3 years ago
Read 2 more answers
g A 1.45-kg block is pushed against a vertical wall by means of a spring (k = 860 N/m). The coefficient of static friction betwe
olga_2 [115]

Answer:

The minimum compression is  x= 0.046m

Explanation:

From the question we are told that

              The mass of the block is m_b = 1.45 kg

               The spring constant is  k = 860 N/m

               The coefficient of static friction is  \mu = 0.36

For the the block not slip it mean the sum of forces acting on the  horizontal axis is equal to the forces acting on the vertical axis

     Now the force acting on the vertical axis is the force due to gravity which is mathematically given as

                   F_y = m_b*g

And the force acting on the horizontal axis is  force due to the spring which is mathematically represented as

                   F_x = k *x * \mu

where x is the minimum compression to keep the block from slipping

        Now equating this two formulas and making x the subject

                      x = \frac{m_b * g}{k * \mu}

substituting values we have

                     x = \frac{1.45 * 9.8}{860 *0.36}

                        x= 0.046m

 

3 0
4 years ago
a child in a tree house uses a rope attached to a basket to lift a 26 nn dog upward through a distance of 5.0 mm into the house.
agasfer [191]

Total work done is 0.13 Joules

<h3>What is work done ?</h3>

The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force.

According to the given information

We need to find the work done

work done  = force × distance

We are given,

force  = 26 N

Distance = 0.0005 meter

hence ,

Work done  = 26 × 0.005  

                   = 0.13 Joules

Total work done is 0.13 Joules

To know more about Work done

brainly.com/question/13662169

#SPJ4

4 0
1 year ago
you see a lightning bolt in the sky. You hear a clap of thunder 3 seconds latter. The speed of 330 m/s. How far away was the lig
Naddika [18.5K]
The i got answer is 990m
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3 years ago
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