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3 years ago

PLEASE HELP BRAINLIEST AND 15 points.

Chemistry

1 answer:

PtichkaEL [24]3 years ago

5 0

Answer:

Substance B, boiling point of 105 °C

Explanation:

Non volatile substances have high boiling points

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If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, what temperature is the gas?

iogann1982 [59]

If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 5.2 atm

V= 500 mL =0.5 L

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=?

$Moles = \frac{mass}{molar \;mass}$

$Moles = \frac{45 g}{32}$

Moles = 1.40625

Putting value in the given equation:

$\frac{PV}{RT}=n$

$1.40625= \frac{5.2 \;atm\; X \;0.5 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}$

T= 22.53167034 K= 22.53K

Hence, If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.

Learn more about the ideal gas here:

brainly.com/question/27691721

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7 0

2 years ago

Your weight changes if you travel to the moon because _____.

alexgriva [62]

Answer:

1/6 of your weight on Earth

4 0

3 years ago

Read 2 more answers

A solution prepared by dissolving 0.100 mole of propionic acid in enough water to make 1.00 L of solution is observed to have a

torisob [31]

Answer:

C) $k_a=1.3\times 10^{-5}$

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

$pH=-log(\sqrt{k_a\times C})$

Where, C is the concentration = 0.5 M

Given, pH = 2.94

Moles = 0.100 moles

Volume = 1.00 L

So, $Molarity=\frac{Moles}{Volume}=\frac{0.100}{1.00}\ M=0.100\ M$

C = 0.100 M

$2.94=-log(\sqrt{k_a\times 0.100})$

$\log _{10}\left(\sqrt{k_a0.1}\right)=-2.94$

$\sqrt{0.1}\sqrt{k_a}=\frac{1}{10^{2.94}}$

$k_a=1.3\times 10^{-5}$

4 0

3 years ago

How many valence electrons does He have

horsena [70]

Answer:

2 valence electrons

3 0

3 years ago

Calculate the value of the diffusion coefficient D (in m2/s) at 547°C for the diffusion of some species in a metal; assume that

svetlana [45]

Answer : The value of diffusion coefficient is, $2.97\times 10^{-16}m^2/s$

Explanation :

Formula used :

$D=D_o\times \exp \left(-\frac{Q_d}{RT}\right )$

where,

D = diffusion coefficient = ?

$D_o$ = $5.6\times 10^{-5}m^2/s$

$Q_d$ = $177kJ/mol$

R = gas constant = 8.314 J/mol.K

T = temperature = $547^oC=273+547=820K$

Now put all the given values in the above formula, we get:

$D=5.6\times 10^{-5}m^2/s\times \exp \left(-\frac{177kJ/mol}{(8.314J/mol.K)\times (820K)}\right )$

$D=2.97\times 10^{-16}m^2/s$

Thus, the value of diffusion coefficient is, $2.97\times 10^{-16}m^2/s$

6 0

3 years ago