Quadratic f(x) = (x -h)² +k has vertex (h, k) and axis of symmetry x=h. When k is negative, the number of real solutions is 2, because both branches of the function cross the x-axis.
In your equation, h = -3 and k = -8.
Axis of symmetry: x = -3
Vertex: (-3, -8)
Number of real solutions: 2
Answer:
x=1; y=2; z=3
Step-by-step explanation:
Rearrange for convince:
2y-4z+6x = -2
-4y+2z-3x=-5
-6y+3z+4x=1
Now we take to pairs and eliminate the same var.:
2y-4z+6x = -2 *2
-4y+2z-3x=-5
and
-4y+2z-3x=-5 *-3
-6y+3z+4x=1. *2
We get:
4y-8z+12y=-4
-4y+2z-3x=-5
= -6z+9x=-9
and
12y-6x+9x=15
-12y+6x+8x=2
= 17x=17
We now know x = 1, so z is:
-6z+9=-9
-6z=-18
z=3
Let’s grab the first formula and find y:
6+2y-12=-2
6+2y=10
2y=4
y = 2
Answer:
256
Step-by-step explanation:
16 ×16= 256
Hope it works out for you
Answer:
14 sq inches
Step-by-step explanation:
you have the top and bottom = 2
then 3 * 4 for the sides, front, and back = 12
add them together and you have 14
thats for the parts you can see on the outside. i hope i did this right
Answer:
1/3
Step-by-step explanation:
To get no solution, you want to get rid of x and leave an incorrect equation.
In this case, we will use 1/3x.
1/3x + 2 = 1/3x - 3
We subtract 1/3x on both sides. This will cause the 1/3x's to cancel out.
1/3x - 1/3x + 2 = 1/3x - 1/3x - 3
2 ≠ -3
As we know, 2 is not 3. Therefore, there is no solution if 1/3x is used.
