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Tanya [424]
3 years ago
5

Need help with this!!

Mathematics
1 answer:
lord [1]3 years ago
6 0

Answer:

last one

Step-by-step explanation:

the domain includes all real numbers and the range is y>0

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What is the approximate distance between the points (-5,1) and (-2,3) on a coordinate grid? Show me an example please
yaroslaw [1]

Answer:

d=\sqrt{13}\ units   or  d=3.61\ units

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

A(-5,1)\\E(-2,3)  

substitute the values

d=\sqrt{(3-1)^{2}+(-2+5)^{2}}

d=\sqrt{(2)^{2}+(3)^{2}}

d=\sqrt{13}\ units

d=3.61\ units

the graph in the attached figure  

4 0
3 years ago
Can someone give the answer to question 2
Natasha_Volkova [10]

Step-by-step explanation:

try doing a2+b2=c2 it will help

3 0
3 years ago
Jane and Lee had dinner at The Palace The bill totaled $20 30 with tax The service
kirza4 [7]

Answer:

$3.45

Step-by-step explanation:

$20.30 / 10  = $2.30 = 10%

$2.30 / 2  = $1.15 = 5%

$2.30 + $1.15 = $3.45 = 15%

3 0
3 years ago
Dilate Point B by a scale factor of 1/2
Sauron [17]

Answer:

B

Step-by-step explanation:

Divide each coordinate by 2

3/2=1.5

2/2=1

8 0
3 years ago
Explain the rule in solving inequalities with a negative coefficient.
dimulka [17.4K]

Answer:

  the comparison must be reversed when multiplying by a negative

Step-by-step explanation:

The rules of equality apply to solving inequalities, with the exception that multiplication or division by a negative number reverses the sense of the comparison:

  -x > 1

  x < -1 . . . . . multiply both sides by -1

____

Effectively, multiplication (or division) by a negative number is equivalent to reflection across the origin. Things that were ordered left/right (on the number line) are ordered right/left after such a reflection:

  -2 < -1

  1 < 2

_____

<em>Additional comment</em>

Application of any function requires that you pay attention to ordering. Some functions naturally reverse the order; others do so only on specific domains.

Consider f(x) = 1/x.

  1 < 2

  f(1) > f(2) . . . . because the slope of the f(x) function is negative everywhere.

__

<em>In the first and second quadrants</em>, the cosine function also reverses order.

  20° > 10°

  cos(20°) < cos(10°)

__

Probably the most commonly encountered function used with inequalities is the absolute value function.

  |x-3| > 2

This function has one domain where the slope is negative, and another domain where the slope is positive.

  For x < 3, the function negates its argument, so we have ...

     -(x -3) > 2

     -x +3 > 2

     -x > -1

     x < 1 . . . . . everywhere consistent with x < 3

  For x ≥ 3, the function does nothing, so we have ...

     x -3 > 2

     x > 5

  The solution to this absolute value inequality is (x < 1) ∪ (x > 5).

__

You can also resolve negative coefficients by adding the opposite. Addition and subtraction never require any change to the comparison operator.

  -x > 1

  0 > x +1 . . . . x is added

  -1 > x . . . . . . -1 is added

7 0
3 years ago
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