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erastova [34]
3 years ago
14

The blank spaces say absorbed from and released to

Chemistry
1 answer:
ryzh [129]3 years ago
6 0

Explanation:

• In an exothermic reaction, energy is released in the surroundings.

• In an endothermic reaction, energy is absorbed from the surroundings.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em> </em>

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What is the molecular structure of water? What are the physical and chemical properties of water?
Slav-nsk [51]
Water (H
2O) is a polar inorganic compound that is at room temperature a tasteless and odorless liquid, which is nearly colorless apart from an inherent hint of blue. It is by far the most studied chemical compound and is described as the "universal solvent" [18][19] and the "solvent of life".[20] It is the most abundant substance on Earth[21] and the only common substance to exist as a solid, liquid, and gas on Earth's surface.[22] It is also the third most abundant molecule in the universe.[21]

Water (H
2O)





NamesIUPAC name

water, oxidane

Other names

Hydrogen hydroxide (HH or HOH), hydrogen oxide, dihydrogen monoxide (DHMO) (systematic name[1]), hydrogen monoxide, dihydrogen oxide, hydric acid, hydrohydroxic acid, hydroxic acid, hydrol,[2] μ-oxido dihydrogen

Identifiers

CAS Number

7732-18-5 

3D model (JSmol)

Interactive image

Beilstein Reference

3587155ChEBI

CHEBI:15377 

ChEMBL

ChEMBL1098659 

ChemSpider

937 

Gmelin Reference

117

PubChem CID

962

RTECS numberZC0110000UNII

059QF0KO0R 

InChI

InChI=1S/H2O/h1H2 

Key: XLYOFNOQVPJJNP-UHFFFAOYSA-N 

SMILES

O

Properties

Chemical formula

H
2OMolar mass18.01528(33) g/molAppearanceWhite crystalline solid, almost colorless liquid with a hint of blue, colorless gas[3]OdorNoneDensityLiquid:[4]
0.9998396 g/mL at 0 °C
0.9970474 g/mL at 25 °C
0.961893 g/mL at 95 °C
Solid:[5]
0.9167 g/ml at 0 °CMelting point0.00 °C (32.00 °F; 273.15 K) [a]Boiling point99.98 °C (211.96 °F; 373.13 K) [6][a]SolubilityPoorly soluble in haloalkanes, aliphaticand aromatic hydrocarbons, ethers.[7]Improved solubility in carboxylates, alcohols, ketones, amines. Miscible with methanol, ethanol, propanol, isopropanol, acetone, glycerol, 1,4-dioxane, tetrahydrofuran, sulfolane, acetaldehyde, dimethylformamide, dimethoxyethane, dimethyl sulfoxide, acetonitrile. Partially miscible with Diethyl ether, Methyl Ethyl Ketone, Dichloromethane, Ethyl Acetate, Bromine.Vapor pressure3.1690 kilopascals or 0.031276 atm[8]Acidity (pKa)13.995[9][10][b]Basicity (pKb)13.995Conjugate acidHydroniumConjugate baseHydroxideThermal conductivity0.6065 W/(m·K)[13]

Refractive index (nD)

1.3330 (20 °C)[14]Viscosity0.890 cP[15]Structure

Crystal structure

Hexagonal

Point group

C2v

Molecular shape

Bent

Dipole moment

1.8546 D[16]Thermochemistry

Heat capacity (C)

75.375 ± 0.05 J/(mol·K)[17]

Std molar
entropy (So298)

69.95 ± 0.03 J/(mol·K)[17]

Std enthalpy of
formation (ΔfHo298)

−285.83 ± 0.04 kJ/mol[7][17]

Gibbs free energy (ΔfG˚)

−237.24 kJ/mol[7]
6 0
3 years ago
I need help filling out nitrogen
xxMikexx [17]
For Nitrogen Atom:
Atomic Number - 7
Protons - 7
Neutrons - 8
Electrons - 7
Cation/Anion - Anion

For Nitrogen Ion:
Atomic Number - 7
Protons - 7
Neutrons - 8
Electrons - 10
Atomic Symbol - N3-
5 0
3 years ago
Many fundamental concepts are at the heart of chemistry. Match the description to the name.
Lisa [10]

Answer:

you dony have a picture for me to match them

Explanation:

4 0
2 years ago
When 10g of calcium carbonate is heated,4.4g of carbon dioxide escape out. The amount of residue left is:
Maslowich
The dissociation of calcium carbonate, CaCO3, to simpler compounds can be expressed as,
                        CaCO3 --> CaO + CO2
The precipitate is CaO and its amount is calculated through the difference which will give us the answer of 5.6 g. 
8 0
3 years ago
Find the mass of benzene (C6H6) required to produce 2.66 g of carbon dioxide gas from the reaction described by the following eq
Sergio039 [100]

Answer:

Mass of benzene required = 0.78 g

Explanation:

Given data:

Mass of CO₂ produced = 2.66 g

Mass of benzene required = ?

Solution:

Chemical equation:

2C₆H₆ + 15O₂       →    6H₂O + 12CO₂

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 2.66 g/ 44 g/mol

Number of moles = 0.06 mol

Now we will compare the moles of CO₂ with C₆H₆.

                        CO₂       :        C₆H₆

                            12        :          2

                          0.06      :        2/12×0.06=0.01 mol

Mass of benzene required:

Mass = number of moles × molar mass

Mass = 0.01 mol × 78.11 g/mol

Mass = 0.78 g

3 0
3 years ago
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