What is the formula of a compound formed between nitrogen (N) and barium (Ba)?
2 answers:
Answer:
Ba3N2
Explanation:
Barium is a metal element and Nitrogen is a non-metal element, so they forme an ionic compound. To make the formula of an ionic compound, first we need to see the valence of the atoms, that is, how much electrons it can donate or it has to gain to have 8 electrons in the valence layer (octet rule).
Barium is in the family 2, so it has two electrons in its valence layer, so it must donate these two electrons; Nitrogen is in the family 15, so it has 5 electrons ins its valence layer and must gain 3 electrons.
Writing the ions they must form:
First came the cation (positive charge), then the anion (negative charge), and the charges must change between them, without the signal, and will inform how many atoms are necessary of which element:
Ba3N2
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<u>Answer:</u> The edge length of the unit cell is 0.461 nm
<u>Explanation:</u>
We are given:
Atomic radius of iridium = 0.163 nm
To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:
Putting values in above equation, we get:
Hence, the edge length of the unit cell is 0.461 nm
Answer:
Described by a redox reaction below
Explanation:
Iron(III) oxide is an ionic compound, since it consists of a metal, iron, and a nonmetal, oxygen.
Ionic compounds are formed when metals lose their valence electrons in order to have an octet in their previous shell and donate them to nonmetal atoms, so that nonmetals fill their outer shell to have an octet.
As a result, positive ions (cations) and negative ions (anions) are formed. When iron reacts with oxygen, the following reaction takes place:
This is a redox (oxidation–reduction) reaction, since we have electron loss and gain. Four iron atoms lose a total of 12 electrons to obtain a +3 charge in the final compound, while 3 oxygen molecules gain these 12 electrons to become 6 oxide anions with a -2 charge.