There are 66 neutrons in a single atom of indium-115. The atomic number of indium-115 is 49, meaning there are 49 protons. Then the atomic mass is 115, so 115-49 = 66.
Rutherford performed gold foil experiment to understand that how negative and positive particles could Co exist in an atom. He bombarded alpha particles on a 0.00004 cm thick gold foil.
He proposed a planetary model of the atom and concluded following results and demonstrated that,
1. An atom produces a line spectrum.
2. An Electron revolves around the nucleus without any orbits.
3. Since most of the particles passed through the foil undeflected it means that most of the volume occupied by an atom is empty.
4. An Atom as a whole is neutral.
5. The deflection of few particles on the foil suggested that there is center of positive particles in an atom called the nucleus of the atom.
6. The complete rebounce of few particles on the gold foil suggested that the nucleus is very dense and hard.
Molarmass of beryllium is 9.0
molar mass of silicon is 28.4
molar mass of calcium is 40.1
molar mass of rhodium is 103.
Answer:
If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)
Explanation:
Step 1: Data given
Number of moles iron (III) oxide (Fe2O3) = 0.66 moles
Step 2: The balanced equation
4Fe + 3O2 → 2Fe2O3
Step 3: Calculate moles of oxygen (O2)
For 4 moles Fe consumed, we need 3 moles of O2 to produce 2 moles of Fe2O3
For 0.66 moles Fe2O3 produced, we need 3/2 * 0.66 = 0.99 moles of O2
If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)