It takes around 4 seconds for the camera ro fall 250 feet
use the quadratic formula where a=-16 b=0 and c=250
Answer:
Copper atoms lose electrons to sulfur atoms
Explanation:
a p e x (:
FIrst, just write down what we know :)
1. 1 mile = 1.6klm
2. There are 3600 seconds in an hr (<em>60s x 60mins = 3600</em>).
Now to get to <em>meters per second</em> (m/s) we need to first work out <em>meters per </em><em>hr</em> (simply convert miles to klm and then multiply by 1000)<em>.</em>
60 x 1.6 = 96 klm/hr x 1000 = 96,000 meters/hr
Now we know this, we can simply divide the meters per hr by <em>how many seconds there are in 1hr</em> to get meters per second:
96000 / 3600 = 26.67m/s
Parta a.
Equation: F = G*m1*m2/d^2
Where
F = 32 N
G = 6.67*10^-11 N.m^2/kg^2
m1 = 9.0*10^13kg
m2 =370 kg
d = distance that separate the center of the two objects.
d^2 = G*m1*m2 / F = 6.67*10^-11 N.m^2/kg^2 * 9.0*10^13 kg *370 kg / 32N = 69,409.69 m^2
d = √69,409.69m^2 = 263.5 m
Part B.
The gravitational field of the comet is g = G*m1/d^2
Notice that it does not depend on the mass of other objects.
Notice also that I will use a distance of 5.0 * 10^3 km, because I think that that is the number that you intended to write in the part b. If that is not the number you can put the right number instead because the solution is written step by step.
g = (6.67*10^-11 N*m^2/kg^2)*(9.0*10^13kg)/(5.0*10^3*10^3m)^2 = 2.4*10^-4 N/kg = 2.4*10^-4 m/s^2
Answer
given,
wavelength = λ = 18.7 cm
= 0.187 m
amplitude , A = 2.34 cm
v = 0.38 m/s
A) angular frequency = ?
angular frequency ,
ω = 2π f
ω = 2π x 2.03
ω = 12.75 rad/s
B) the wave number ,
C)
as the wave is propagating in -x direction, the sign is positive between x and t
y ( x ,t) = A sin(k x - ω t)
y ( x ,t) = 2.34 x sin(33.59 x - 12.75 t)