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faltersainse [42]
3 years ago
10

What type of radiation is lead emitting in the following equation? ​

Chemistry
2 answers:
Tom [10]3 years ago
7 0
The answer is B, beta particles. hope this helps and have a good day
qaws [65]3 years ago
5 0

Answer: B, it is beta particles

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Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these
deff fn [24]
The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

     N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
   Hrxn = Hproduct - Hreactant

Since all the reactants are in their elemental forms, the simplified equation would be,

    Hrxn = Hproduct 

Substituting,

    Hrxn = (-186.81 kJ/mol)(2 mols)

<em>Answer: -372.42 kJ</em>

7 0
3 years ago
Which statement is true? Nuclear power plants require more fuel than conventional power plants. There is a short supply of high
Bas_tet [7]
I believe the correct answer would be option 4. The only statement that is true would be that it is difficult to responsibly dispose of nuclear waste products. This is because nuclear waste products are radioactive and are very harmful to the society and to the environment. It could cause serious damage to every being in contact to it.
3 0
3 years ago
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Which of the following is an irreversible physical change?
Yuliya22 [10]

Answer:

b) sharpening a pencil

Explanation:

If you melt lead, boil water, or dissolve sugar in water, you can return all of them back to their original state. If you sharpen a pencil, you can't reattach the shavings as they were originally.

3 0
3 years ago
The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Esti
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Zeff = Z - S

Here, Z is the number of protons in the nucleus, that is, atomic number, and S is the number of nonvalence electrons.

For boron, the electronic configuration is 1s₂ 2s₂ 2p₄

Z = 5, S = 2

Zeff = 5-2 = +3

For O, electronic configuration is 1s₂ 2s₂ 2p₄

Z = 8, S = 2

Zeff = 8-2 = +6

Hence, the correct answer is second option, that is, +3 and +6, the Zeff of boron is smaller in comparison to O, thus, boron exhibits a bigger size than O.

3 0
3 years ago
What volume is occupied by 2.33 moles of an ideal gas at 0.953 atm
nekit [7.7K]

Answer:

WhAT

Explanation:

WTH

4 0
3 years ago
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