Answer:
The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L
Explanation:
Given data:
Number of moles of HF = 6.62×10⁻³ mol
Volume of HF in litter at STP = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Standard temperature = 273 K
Standard pressure = 1 atm
Now we will put the values in formula.
1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K
V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm
V = 148.38×10⁻³ L
Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.
Answer:
The answer to your question is: b. P - Br
Explanation:
Difference of electronegativities from the periodic table. The one with the highest electronegativity will be the most polar.
a.
H = 2.2
Se = 2.55
Electronegativity = 2.55 - 2.2 = 0.35
b.
P = 2.19
Br = 2.96
Electronegativity = 2.96 - 2.19 = 0.77
c.
N = 3.04
I = 2.66
Electronegativity = 3.04 - 2.66 = 0.38
This can’t have a answer unless u change them into another number of Delanece
Polyatomic ion: a covalently bonded group of atoms that has a positive or negative charge and acts as a unit.
