Answer:
1.98x10⁻¹² kg
Explanation:
The <em>energy of a photon</em> is given by:
h is Planck's constant, 6.626x10⁻³⁴ J·s
c is the speed of light, 3x10⁸ m/s
and λ is the wavelenght, 671 nm (or 6.71x10⁻⁷m)
- E = 6.626x10⁻³⁴ J·s * 3x10⁸ m/s ÷ 6.71x10⁻⁷m = 2.96x10⁻¹⁹ J
Now we multiply that value by <em>Avogadro's number</em>, to <u>calculate the energy of 1 mol of such protons</u>:
- 1 mol = 6.023x10²³ photons
- 2.96x10⁻¹⁹ J * 6.023x10²³ = 1.78x10⁵ J
Finally we <u>calculate the mass equivalence</u> using the equation:
- m = 1.78x10⁵ J / (3x10⁸ m/s)² = 1.98x10⁻¹² kg
Answer:
B.
Explanation:
the SI unit for density is the kilogram per Cubic meter
The balanced equation for reaction of chlorine gas with fluorine gas is written as follows
Cl2(g) + 3 F2(g) = 2ClF3(g)
chlorine react with flourine to form CIF3 . The phases of reactant and product is the gas phase
Answer:
Volume occupied by 10 grams of Lithium Oxide at STP is 7.52 L
Explanation:
STP (Standard Temperature and Pressure) : It is used while performing calculation on gases and provide standards of measurements while performing experiment.
According to IUPAC (International Union of Pure And applied Chemistry) , standard temperature is 273.15 K and Pressure is 100 kPa (0.9869 atm). At STP condition 1 mole of substance occupies 22.4 L volume .
Molar mass of Lithium Oxide = 29.8 g/mol
= 2(6.9) + 15.99 = 29.8
Mass of 1 mole = 29.8 g
1 mole occupies, Volume = 22.4 L
29.8 g occupies, V = 22.4 L
1 g occupies ,V = 
1 g occupies ,V = 0.7516 L
10 g tex]Li_{2}O[/tex] occupies ,V = 
L
V = 7.52 L
So, volume occupied by Lithium Oxide At STP is 7.52 L
