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3 years ago

Ow do quantum numbers relate to electrons?

Physics

1 answer:

strojnjashka [21]3 years ago

3 0

They enable us to dig deeper into the electron configurations by making us focus on electrons' quantum nature

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What is the equator ?????e define

pav-90 [236]

$\bold{ANSWER}$

EQUATOR IS THE LINE THAT DIVIDES EARTH INTO TWO HEMISPHERES .

7 0

3 years ago

A specimen of steel has a rectangular cross section 20 mm wide and 40 mm thick, an elastic modulus of 207 GPa, and a Poisson’s r

katrin2010 [14]

Answer:

There's a decrease in width of 2.18 × 10^(-6) m

Explanation:

We are given;

Shear Modulus;E = 207 GPa = 207 × 10^(9) N/m²

Force;F = 60000 N.

Poisson’s ratio; υ =0.30

We are told width is 20 mm and thickness 40 mm.

Thus;

Area = 20 × 10^(-3) × 40 × 10^(-3)

Area = 8 × 10^(-4) m²

Now formula for shear modulus is;

E = σ/ε_z

Where σ is stress given by the formula Force(F)/Area(A)

While ε_z is longitudinal strain.

Thus;

E = (F/A)/ε_z

ε_z = (F/A)/E

ε_z = (60,000/(8 × 10^(-4)))/(207 × 10^(9))

ε_z = 3.62 × 10^(-4)

Now, formula for lateral strain is;

ε_x = - υ × ε_z

ε_x = -0.3 × 3.62 × 10^(-4)

ε_x = -1.09 × 10^(-4)

Now, change in width is given by;

Δw = w_o × ε_x

Where w_o is initial width = 20 × 10^(-3) m

So; Δw = 20 × 10^(-3) × -1.09 × 10^(-4)

Δw = -2.18 × 10^(-6) m

Negative means the width decreased.

So there's a decrease in width of 2.18 × 10^(-6) m

6 0

3 years ago

In the picture at left. The launch height is 10m ball B mass 5kg has a launch velocity of 12 m/s and ball A mass 8 kg has a laun

Hitman42 [59]

Answer:

Explanation:

8 0

3 years ago

Your friend tells you “I no the moon does not rotate because we always see the same side.” do you agree or disagree with your fr

nydimaria [60]

Answer:

no the moon does not rotate it only goes in circle just like the sun so I disagree with your friend

3 0

3 years ago

Two cellists, one seated directly behind the other in an orchestra, play the same 220-Hz note for the conductor who is directly

Llana [10]

Answer:

d= 1.56 m

Explanation:

In order to have a constructive interference, the path difference between the sources of the sound, must be equal to an even multiple of the semi-wavelength, as follows:

⇒ d = d₂ - d₁ = 2n*(λ/2)

The minimum possible value for this distance, is when n=1, as it can be seen here:

dmin = λ

In any wave, there exists a fixed relationship between the wave speed, the frequency and the wavelength:

v = λ*f

If v = vsound = 343 m/s, and f = 220 1/s, we can solve for λ:

λ = $\frac{v}{f} = \frac{343 m/s}{220(1/s)} = 1.56 m$

⇒ dmin =λ = 1.56 m

3 0

3 years ago