Answer:
0.17547 m
Explanation:
m = Mass of block = 
v = Velocity of block = 10.8 m/s
k = Spring constant = 125 N/m
A = Amplitude
The kinetic energy of the system is conserved

The amplitude of the resulting simple harmonic motion is 0.17547 m
D
Giddy UP!!!!!!!!!!!!!!!!!!!!!
Answer:
the force of the friction is A-0.52