The increase in temperature of the metal hammer is 0.028 ⁰C.
The given parameters:
- <em>mass of the metal hammer, m = 1.0 kg</em>
- <em>speed of the hammer, v = 5.0 m/s</em>
- <em>specific heat capacity of iron, 450 J/kg⁰C</em>
The increase in temperature of the metal hammer is calculated as follows;
where;
<em>c is the </em><em>specific heat capacity</em><em> of the metal hammer</em>
<em />
Assuming the metal hammer is iron, c = 450 J/kg⁰C
Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.
Learn more about heat capacity here: brainly.com/question/16559442
Answer:
a) v = 0.4799 m / s, b) K₀ = 1600.92 J, K_f = 5.46 J
Explanation:
a) How the two players collide this is a momentum conservation exercise. Let's define a system formed by the two players, so that the forces during the collision are internal and also the system is isolated, so the moment is conserved.
Initial instant. Before the crash
p₀ = m v₁ + M v₂
where m = 95 kg and his velocity is v₁ = -3.75 m / s, the other player's data is M = 111 kg with velocity v₂ = 4.10 m / s, we have selected the direction of this player as positive
Final moment. After the crash
p_f = (m + M) v
as the system is isolated, the moment is preserved
p₀ = p_f
m v₁ + M v₂ = (m + M) v
v =
let's calculate
v = 
v = 0.4799 m / s
b) let's find the initial kinetic energy of the system
K₀ = ½ m v1 ^ 2 + ½ M v2 ^ 2
K₀ = ½ 95 3.75 ^ 2 + ½ 111 4.10 ^ 2
K₀ = 1600.92 J
the final kinetic energy
K_f = ½ (m + M) v ^ 2
k_f = ½ (95 + 111) 0.4799 ^ 2
K_f = 5.46 J
When the bus starts moving forward, the man remains at rest,
causing him to lean back.
When the bus slows down, the man continues to move forward,
and appears to lean forward.
Both events are examples of the effect of inertia.
It is Yellow, Cyan, Magenta . The answer is D.
Answer:
c. V = k Q1 * Q2 / R1 potential energy of Q1 and Q2 separated by R
V2 / V1 = (R1 / R2) = 1/4
V2 = V1 / 4
