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mars1129 [50]
3 years ago
7

If a train travels 80 miles north, 60 miles east, what’s the magnitude of its total displacement? Find the solution by drawing a

diagram. ____ miles.

Physics
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

100 miles North East.

Explanation:

Please see attached photo for diagram.

In the attached photo, X represents the magnitude of the total displacement of the train.

Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:

X² = 80² + 60²

X² = 6400 + 3600

X² = 10000

Take the square root of both side

X = √10000

X = 100 miles.

Therefore, the magnitude of the total displacement of the train is 100 miles North East.

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Study the interaction of the light rays with the mediums. Classify the medium in each image as being transparent or opaque.
Tresset [83]

Answer:

a) transparent

b) transparent

c) opaque

Explanation:

In the first one, the light rays go completely through, so it is transparent.

The second one I'm not too sure about. It is refraction so it's going through a different material, but the fact that it went through makes me say transparent.

Last one, the light rays are reflecting off the surface so it's opaque.

Please feel free to correct me if I'm wrong. This is just my understanding

6 0
3 years ago
Read 2 more answers
Hello people ~<br>Sound cannot travel through<br>(a) air<br>(b) water<br>(c) air<br>(d) vacuum​
SVETLANKA909090 [29]

Answer:

Vaccum

Explanation:

  • Sound travels through the particles of different matter
  • In vaccum there is no air so no matter and so no particles .
  • So sound can't travel through vaccum.

You can test it .

  • Take a speaker and keep it inside a bottle ,close it .
  • You won't hear any sound
7 0
2 years ago
Read 2 more answers
A hockey puck with a mass of 0.16 kg travels at a velocity of 40 m/s toward a goalkeeper. The goalkeeper has a mass of 120 kg an
Ainat [17]

Answer:

Explanation:

Momentum is the product of mass of a body and its velocity.

Given the mass of the puck m1 = 0.16kg

velocity of the puck v1 = 40m/s

Given the mass of the goalkeeper m2 = 120kg

velocity of the goalkeeper v2= 0m/s (goal keeper at rest)

The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is expressed as:

m1v1 + m2v2 (their momentum will be added since they collide)

= 0.16(40) + 120(0)

= 0.16(40) + 0

= 6.4kgm/s

Let us calculate their common velocity using the conservation of momentum formula;

m1u1 + m2u2 = (m1+m2)v

6.4 = (0.16+120)v

6.4 = 120.16v

v = 6.4/120.16

v = 0.053m/s

Hence after collision, both objects move at a velocity of 0.053m/s

Momentum of the puck after collision = m1v

Momentum of the puck after collision = 0.16*0.053m/s

Momentum of the puck after collision = 0.0085kgm/s

Momentum of the keeper after collision = m2v

Momentum of the keeper after collision = 120*0.053m/s

Momentum of the keeper after collision = 6.36kgm/s

From the calculation above, it can be seen that the keeper has the greater momentum after the puck was caught since the momentum of the keeper after collision is greater than that of the puck

4 0
3 years ago
A runner has an initial velocity of 4 meters per second. After 20 seconds, the runner's velocity is 6 meters per second. Which i
jasenka [17]

Answer:

B. 0.1 meters/second/second in the same direction of travel.

Explanation:

Acceleration is the rate of change of velocity. Acceleration is a vector quantity.

a=Δv/Δt

=(v₂-v₁)/(t₂-t₁)

v₁=4 m/s

v₂=6 m/s

t₁=0 s

t₂=20 s

a=(6m/s-4m/s)/(20s-0)

= 0.1 m/s² in the same direction of travel.

Therefore acceleration =0.1 meters/second/second in the same direction of travel.

7 0
3 years ago
Read 2 more answers
Resistance to the motion of an automobile consists of road friction, which is almost independent of speed, and air drag, which i
Troyanec [42]

Answer:

73.52983 Hp

Explanation:

m = Mass of car = \dfrac{W}{g}

W = Weight of car = 12000 N

a = Acceleration = 0.96 m/s²

Velocity of the car

v=82\times \dfrac{1000}{3600}\\\Rightarrow v=\dfrac{82}{3.6}\\\Rightarrow v=\dfrac{41}{1.8}

From the question

F=300+1.8v^2\\\Rightarrow F=300+1.8\times \left(\dfrac{41}{1.8}\right)^2\\\Rightarrow F=1233.88\ N

Balancing the forces

\dfrac{P}{v}-1233.88=ma\\\Rightarrow P=(ma+12000)v\\\Rightarrow P=\left(\dfrac{12000}{9.81}\times 0.96+1233.88\right)\dfrac{41}{1.8}\\\Rightarrow P=54853.26055\ W=\dfrac{54853.26055}{746}\\\Rightarrow P=73.52983\ Hp

The power is 73.52983 Hp

6 0
3 years ago
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