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mars1129 [50]
3 years ago
7

If a train travels 80 miles north, 60 miles east, what’s the magnitude of its total displacement? Find the solution by drawing a

diagram. ____ miles.

Physics
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

100 miles North East.

Explanation:

Please see attached photo for diagram.

In the attached photo, X represents the magnitude of the total displacement of the train.

Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:

X² = 80² + 60²

X² = 6400 + 3600

X² = 10000

Take the square root of both side

X = √10000

X = 100 miles.

Therefore, the magnitude of the total displacement of the train is 100 miles North East.

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Which of the following represent units of an electric field? select all that apply
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Answer:

Volts/Meter

Newtons/Coulomb

Explanation:

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Electric field strength E is the force per unit charge. It is measured in Newton/Coulomb in SI unit. It is a vector quantity directed in the direction of force.

Mathematically,

           Electric field strength = Force/Charge

                                           E = F / q₀

                                               = Newton / Coulomb = NC⁻¹             1

We know that

                         Newton = Joule/meter            2

Also

                           Volt = Joule/Coulomb             3

So put 3 in 2 we get

                          Newton = (Volt Coulomb)/meter       put in 1

   

                            E =  (Volt Coulomb)/(meter Coulomb)

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Hence

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3 years ago
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In the following description, QUOTE the portion that addresses weather in the area.
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3 years ago
A particle with positive charge q = 9.61 10-19 C moves with a velocity v = (5î + 4ĵ − k) m/s through a region where both a unifo
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Answer:

\vec{F}=(1.537*10^{-17}\hat{i}-9.61*10^{-19}\hat{j}-2.883*10^{-18}\hat{k})N

Explanation:

The total force on the particle is given by

\vec{F}=q\vec{v}\ X\ \vec{B}+q\vec{E}

Then, by replacing we have:

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