If a train travels 80 miles north, 60 miles east, what’s the magnitude of its total displacement? Find the solution by drawing a
diagram. ____ miles.
1 answer:
Answer:
100 miles North East.
Explanation:
Please see attached photo for diagram.
In the attached photo, X represents the magnitude of the total displacement of the train.
Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:
X² = 80² + 60²
X² = 6400 + 3600
X² = 10000
Take the square root of both side
X = √10000
X = 100 miles.
Therefore, the magnitude of the total displacement of the train is 100 miles North East.
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Answer:
I(x) = 1444×k ×
I(y) = 1444×k ×
I(o) = 3888×k ×
Explanation:
Given data
function = x^2 + y^2 ≤ 36
function = x^2 + y^2 ≤ 6^2
to find out
the moments of inertia Ix, Iy, Io
solution
first we consider the polar coordinate (a,θ)
and polar is directly proportional to a²
so p = k × a²
so that
x = a cosθ
y = a sinθ
dA = adθda
so
I(x) = ∫y²pdA
take limit 0 to 6 for a and o to for θ
I(x) = y²p dA
I(x) = (a sinθ)²(k × a²) adθda
I(x) = k da ×
(sin²θ)dθ
I(x) = k da ×
(1-cos2θ)/2 dθ
I(x) = k ×
I(x) = k × × (
I(x) = k × ×
I(x) = 1444×k × .....................1
and we can say I(x) = I(y) by the symmetry rule
and here I(o) will be I(x) + I(y) i.e
I(o) = 2 × 1444×k ×
I(o) = 3888×k × ......................2
Answer: d. 8.25 m/s
Explanation:
We are given that Current= 5 m/s in j direction
Velocity= 8 m/s i + 3 m/s j
Now, we have to find Jada's speed with respect to the water.
First we find Jada's velocity with respect to water
v= (8 i + 3 j) - (5 j)
v= 8i - 2 j
To find the speed, we take the magnitude of this velocity vector we have
|v|=
|v|= = 8.246 m/s
which comes out to be around = 8.25 m/s
So option d is correct.