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3 years ago

QUESTION 3 ( MARKS]

Physics

1 answer:

horrorfan [7]3 years ago

7 0

Answer:

392 N

Explanation:

Draw a free body diagram of the rod. There are four forces acting on the rod:

At the wall, you have horizontal and vertical reaction forces, Rx and Ry.

At the other end of the rod (point X), you have the weight of the sign pointing down, mg.

Also at point X, you have the tension in the wire, T, pulling at an angle θ from the -x axis.

Sum of the moments at the wall:

∑τ = Iα

(T sin θ) L − (mg) L = 0

T sin θ − mg = 0

T = mg / sin θ

Given m = 20 kg and θ = 30.0°:

T = (20 kg) (9.8 m/s²) / (sin 30.0°)

T = 392 N

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Zina [86]

Answer:

8 times

Explanation:

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That means the heart will pump 10 quarts in 2 minutes.

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3 years ago

Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.

Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and $g=9.8m/s^2$ the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

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The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

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3 years ago

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2 years ago

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ale4655 [162]

Answer: The degree of the first term.

Explanation:

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The left and right ends would be indicated when x is changed to -x. When this is substituted, the change is indicated by the first term because only the degree of first term is odd.

Let the left hand side be donated by -x.

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3 years ago

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