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Vesnalui [34]
3 years ago
9

An 80 kg skier stands at the top of a 40-meter slope. She then skis down the slope. What is her approximate speed at the bottom

of the slope if friction is negligible and her kinetic energy is 31360 J?
Physics
1 answer:
irinina [24]3 years ago
5 0

Thank you for that information.  If we know her mass and kinetic energy, then we don't need any of that other business about the height of the slope, her skiing ability, the friction of the snow, what she uses to wax her skis, the color of her parka, or what she had for lunch at the chalet.  The mass and kinetic energy are enough to answer the question.

Kinetic Energy = (1/2) · (mass) · (speed)²

31,360 J = (1/2) · (80 kg) · (speed)²

speed² = (31,360 J) / (40 kg)

speed² = 784 m²/s²

speed = <em>28 m/s</em>

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weeeeeb [17]

Answer:

force becomes one - ninth

Explanation:

According to Coulomb's law in electrostatics, two charges can exert a force of attraction or repulsion on each other which is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

Here both the charges remains same but the distance is variable.

So, we can say that

F \alpha \frac{1}{d^{2}}    .... (1)

Where d be the distance between the tow charges

As the distance between two charges increases by factor of three, let the new force be F'.

F' \alpha \frac{1}{9d^{2}}   .... (2)

Divide equation (2) by equation (1), we get

\frac{F'}{F}=\frac{d^{2}}{9d^{2}}

F'=\frac{F}{9}

Thus, the force becomes one - ninth times the initial force.

6 0
3 years ago
a bike is moving with a velocity of 90km/hr.after applying break it stops in 5 sec. calculate the force applied by brakes .mass
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Explanation:

initial velocity(u) = 90 km/s = 25 m/s

time (t) = 5 sec

mass (m) = 200 kg 

final velocity (v) = 0 m/s

v = u + at 

0 = 25 + a * 5

-25 = 5 a

-5 = a

Therefore acceleration = -5m/s²

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F = 200*-5

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7 0
3 years ago
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nata0808 [166]

Answer:

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2 years ago
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zvonat [6]

Answer:

C. The bug's change in momentum is equal to the car's change in momentum.

Explanation:

As we know by Newton's 2nd law

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F_{12} = F_{21}

so we know that

\frac{\Delta P_{12}}{\Delta t} = \frac{\Delta P_{21}}{\Delta t}

so we have

\Delta P_{12} = \Delta P_{21}

so correct answer will be

C. The bug's change in momentum is equal to the car's change in momentum.

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