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4 years ago

14

When an airplane flies from Dallas - Ft. Worth International airport to Los Angeles International airport, the time in the air i

s 2 hours and 36 minutes. The distance covered is 1246 miles" What is the average speed?

1 answer:

Elanso [62]4 years ago

7 0

Answer:

7.99 or 8 depends where you round.

Explanation:

Distance divided by time so 1246/156=7.98717948718

You might be interested in

A copper sphere was moving at 25 m/s when it hit another object. this caused all of the ke to be converted into thermal energy f

muminat

ΔT= 81°C was the increase in temperature.

<h3>steps</h3>

As evidenced by energy conservation

To increase its temperature, all of its kinetic energy will be converted to thermal energy.

$\frac{1}{2}mv ^{2} = ms$ ΔT

then divide both sides by the object's mass.

$\frac{1}{2} v^{2} =s$ ΔT

therefore, a temperature shift is described as

ΔT= $V^{2} /2s$

ΔT= $25^{2}$ / 2 x 387

ΔT= 81°C

ΔT= 81°C was the increase in temperature.

learn more about increase in temperature here

<u>brainly.com/question/14319779</u>

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3 0

1 year ago

{WORTH BRAINLIEST WITH AN EXPLANATION} Janine is a police officer patrolling a street. She drives 2.2 km east, then 4.4 km west,

icang [17]

Answer:

Options (3) and (6)

Explanation:

Janine drives 2.2 km East.

Since, distances measured in the East are positive,

Displacement = 2.2 km

Then she drives 4.4 km west

Displacement = -4.4 km

Followed by 1.7 km in the East

Displacement = 1.7 km

Total displacement = 2.2 - 4.4 + 1.7 = -0.5 km

$\overrightarrow{d}=-0.5$ km

Total distance covered by Janine = 2.2 + 4.4 + 1.7 = 8.3 km

d = 8.3 km

Therefore, Options (3) and (6) will be the answer.

5 0

4 years ago

Explain how Newton’s third law describes the motion of a rocket. How could this apply to the motion of a robot on ice?

kolbaska11 [484]

Answer:

According to Newton's third law of motion to every action, there is an equal and opposite reaction. When a rocket moves in free space it ejects hot gases. ... It is then the “reaction force”. As a result, the rocket is accelerated or propelled in the opposite direction.

Launching a rocket relies on Newton's Third Law of Motion. A rocket engine produces thrust through action and reaction. The engine produces hot exhaust gases which flow out of the back of the engine. In reaction, a thrusting force is produced in the opposite reaction.

5 0

3 years ago

A circular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane

Mama L [17]

Answer:

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop, $\phi=8.6\times 10^{-3}\ T/m^2$

The magnetic flux linked through the loop is :

$\phi=B.A$

$\phi=BA\ cos\theta$

Here, $\theta=0$

$B=\dfrac{\phi}{A}$

or

$B=\dfrac{\phi}{\pi r^2}$

$B=\dfrac{8.6\times 10^{-3}}{\pi (0.117 )^2}$

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

4 0

3 years ago

Two wheels with fixed hubs, each having a mass of 1kg , start from rest, and forces are applied: F1= 1 N to the first wheel and

irina [24]

Answer:

2N

Explanation:

$m = m_1 = m_2 = 1 kg$

The torques generated by tangential forces on the 2 wheels are

$T_1 = F_1R_1 = 1*0.5 = 0.5 Nm$

$T_2 = F_2R_2 = F_2*1 = F_2 Nm$

According to Newton's 2nd law, the angular accelerations generated by these torque would be

$\alpha_1 = \frac{T_1}{I_1} = \frac{0.5}{mR_1^2} = \frac{0.5}{1*0.5^2} = 2 rad/s^2$

$\alpha_2 = \frac{T_2}{I_2} = \frac{F_2}{mR_2^2} = \frac{F_2}{1*1^2} = F_2 rad/s^2$

For the 2nd wheel to have the same angular acceleration, its force must be

$\alpha_1 = \alpha_2$

$2 = F_2$

$F_2 = 2N$

6 0

3 years ago