<span>Mass of CH2 = 12 + 2 = 14 g/mol
The number of CH2s there are.
So since the total mass is 84.2 g/mol.
The solution is
84.2/14 = 6.012 thus the answer is 6
There are 6(CH2)
So the molecular formula is C6H12</span>
<em>An example of a</em><em>n</em><em> </em><em><u>exothermic</u></em><em> </em><em>reaction is when metals react with oxygen to form metal</em><em> </em><em><u>Oxides</u></em>
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em>helped you- have a good day bro cya)
Answer #1 is "there is 2.5 grams of solute in every 100 g of solution."
We calculate for 2.5% by mass solution by dividing the mass of the solute by the mass of the solution and then multiply by 100.
Answer #2 is "that mass ratio would be 2.5/100 or 2.5 grams of solute/100 grams of solution."
We weigh out 2.5 grams of solute and then add 97.5 grams of solvent to make a total of 100 gram solution, that is,
mass of solute / mass of solution = 2.5g solute / (2.5g solute + 97.5g solvent)
= 2.5g solute / 100g solution
Answer#3 is "a solution mass of 1 kg is 10 times greater than 100 g, thus one kilogram (1 kg) of a 2.5% ki solution would contain 25 grams of ki."
We multiply 10 to each mass so that 100 grams becomes 1000grams since 1000 grams is equal to 1 kg:
mass of solute / mass of solution = 2.5g*10/[(2.5g*10) + (97.5g*10)]
= 25g solute/(25g solute + 975g solvent)
= 25g solute/1000g solution
= 25g solute/1kg solution
Answer:
M = 1.26
Explanation:
Molarity = mole of solution/liters of solution
435mL/1000 = .435L
Plugging in the numbers into the formula, we get:
Molarity = .550 mol/.435L = 1.26 M
M/V=D
65.14/35.4≈1.84
The density of the sulfuric acid would be about 1.84g/mL
