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Shkiper50 [21]
3 years ago
11

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
1 answer:
mihalych1998 [28]3 years ago
6 0
I’m pretty sure it’s B
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A 5592 N piano is to be pushed up a(n) 3.79 m frictionless plank that makes an angle of 30.1 ◦ with the horizontal. Calculate th
otez555 [7]

Answer:

10628.87 J

Explanation:

We are given that

Force applied =F=5592 N

\theta=30.1^{\circ}

Displacement=D=3.79 m

We have to find the work done in sliding the piano up the plank at a slow constant rate.

Work done=F\times displacement

The perpendicular component of force=FSin\theta=5592sin(30.1)=2804.45N

Work done =Fsin\theta\times D=2804.45\times 3.79=10628.87 J

Hence, the work done in sliding the piano up the plank at a slow constant rate=10628.87 J

8 0
3 years ago
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The successive ionization energies for an unknown element are listed below. To which family in the periodic table does the unkno
bagirrra123 [75]
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4 0
2 years ago
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Hi! Can somebody please help?
dezoksy [38]

Answer:

Diagram A will reach the top first.

Explanation:

If it is going straight, it will go slower. The higher the movement speed the faster it is. Hope this helps!

7 0
2 years ago
A body in simple harmonic motion has a displacement x that varies in time t according to the equation x = 5cos(π t + π/3) , wher
zhuklara [117]

Answer:

1/2 Hz

Explanation:

A simple harmonic motion has an equation in the form of

x(t) = Acos(\omega t - \phi)

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Since our body has an equation of  x = 5cos(π t + π/3) we can equate \omega = \pi and solve for frequency f

2\pi f = \pi

f = 1/2 Hz

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3 years ago
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Is there supposed to be a slit at the top of your adams apple?
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