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Shkiper50 [21]
4 years ago
11

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
1 answer:
mihalych1998 [28]4 years ago
6 0
I’m pretty sure it’s B
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me (5) A taxi is travelling at 15. m/s. Its driver accelerates with acceleration 3 m/s for 4 s. What is its new velocity? A car
photoshop1234 [79]

Answer:

5)

Solution

initial velocity = 15 m/s

acceleration = 3m/s^2

time = 4 s

final velocity = 15+3×4

=15+12

=27m/s

A car accelerates from 20m/s to 30m/s in 10 second

T9 be honest I think some part of the second question is missing

4 0
3 years ago
The density of water is 1.00 g/cm3. What is its density in kg/m3?
sweet [91]

Answer:

The metric system was originally devised so that water would have a density of 1 g/cm3, equivalent to 103 kg/m3.

3 0
3 years ago
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Vygotsky believed that scaffolding limited communication between the teacher and the learner.
spin [16.1K]

Answer: The given statement is False.

Lev Vygotsky gave a socio-cultural theory of cognitive development. According to this theory, socialization or social interaction of individual with people who are more knowledgeable than them plays a significant role in their cognitive development.

He described scaffolding as the support given to child by more knowledgeable others ( like parents or teachers). This means that scaffolding allowed communication between the teacher and the learner.

Thus, the given statement is False.

4 0
4 years ago
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A point charge q1 is at the center of a sphere of radius 20 cm. Another point charge q2 = 5 nC is located at a distance r = 30 c
valina [46]

Answer:

q_1 =7.08*10^{-9}C.

Explanation:

Gauss's Law says that the electric flux \Phi_E through a closed surface is directly proportional to the charge Q_{enc} inside it. More precisely,

$\Phi_E=\oint_S E\cdot dA = \dfrac{Q_{enc}}{\epsilon_0}. $

This means what is outside this closed surface S does not contribute to the flux through it because field lines that go in must come out, <em>resulting a zero flux from an external charge. </em>

In our context, this means the charge q_2 which is outside the sphere will have zero flux through the surface; therefore, Gauss's law will only be concerned with charge q_1 which is inside the sphere; Hence,

$\Phi_E=\oint_S E\cdot dA = \dfrac{q_1}{\epsilon_0} = 800 N\cdot m^2/C. $

Solving for q_1 gives

$ q_1= (800 N\cdot m^2/C)\epsilon_0, $

$ q_1= (800 N\cdot m^2/C)*(8.85*10^{-12}C^2/N\cdot m^2) $

\boxed{q_1 =7.08*10^{-9}C. }

which is the charge inside the sphere.

5 0
3 years ago
wire 1 and 2 are made of the same metal. wire 2 has twice the length and diameter of the of wire 1.what is the ratio R2/R1 of th
Vlada [557]
Since the wires are made up of the same material, the resistivities will be the same.

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