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Kay [80]
2 years ago
6

William made one comment to an employee recently assigned to his team complimenting her on her dress. Later she was reprimanded

for poor performance. She claims that this must have been caused by her refusal to become involved with William. What should William do when the claim is investigated?
A. Quit and find another job.
B. Claim that this employee is unstable.
C. Cooperate fully in the investigation. If the only evidence is one compliment on an employee's choice of clothing, it is not enough to be considered creating a hostile work environment
D. Hire a good lawyer to defend him
Physics
2 answers:
astra-53 [7]2 years ago
7 0

Answer:

The correct option is option is C

Explanation:

As the compliment made by William is only on the dress of the team member, this is not indication of creation of a hostile work environment. As William has done nothing wrong, so he should cooperate fully with the investigation and get his name cleared in this situation.

Option A is not correct as William has done nothing wrong

Option B is not correct as William is not an expert in declaring an employee stable or unstable.

Option D is not correct as involving a lawyer will aggravate the matters and as there is no legal process involved there is no need of a lawyer.

Ilya [14]2 years ago
5 0

Answer:

C

Explanation:

William should fully in the investigation. If the only plausible evidence of sexual harassment  is a subtle compliment of an employee's choice or way of dressing. Such comments may be opinionated but are insufficient or a weak evidence for a sexual harassment case.    

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Two electrons with a charge of magnitude 1.6×10-19 C in an atom are separated by 1.5×10-10 m, the typical size of an atom. What
vesna_86 [32]

Answer:

1.02\cdot 10^{-8} N, repulsive

Explanation:

The magnitude of the electric force between two charged particles is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

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k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges of the two particles

r is the separation between the two charges

The force is:

- repulsive if the two charges have  same  sign

- Attractive if the two charges have opposite signs

In this problem, we have two electrons, so:

q_1=q_2=1.6\cdot 10^{-19}C is the magnitude of the two electrons

r=1.5\cdot 10^{-10} m is their separation

Substituting into the formula, we find the electric force between them:

F=(8.99\cdot 10^9)\frac{(1.6\cdot 10^{-19})^2}{(1.5\cdot 10^{-10})^2}=1.02\cdot 10^{-8} N

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