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baherus [9]
4 years ago
10

Which is belief held by sociologists who work from a social-conflict perspective

Physics
2 answers:
Ksju [112]4 years ago
7 0
Some social patterns are helpful, while others are harmful.
marysya [2.9K]4 years ago
4 0

Answer:

Social Structures provide a necessary framework for life

Explanation:

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A guitar string with a length of 80.0 cm is plucked. The speed of a wave in the string is 400 m/sec. Calculate the frequency of
Sholpan [36]

Answer:

The first harmonic is: 250Hz, second harmonic 500Hz, third harmonic 750Hz.

Explanation:

Use the frequency f, speed v, and wavelentgh L relationship:

v = f\cdot L\implies f = \frac{v}{L}

We are given the speed v=400 m/s. The base wavelength on a string of length 80cm is twice the length of the string (a "half wave" along the full length of the string), so:

f = \frac{400\frac{m}{s}}{2\cdot0.8 m}= 250\frac{1}{s}=250 Hz

The fundamental frequency (first harmonic) is 250 Hz

The second harmonic is produced by one full wave across the string (adding one node in the middle), so L=80cm in this case, therefore the second harmonic frequency is: f2 = 2*250=500Hz

the third harmonic add another node (and a half wave) to the pattern and the wavelength will be 2/3 of 80cm, so f3=3*250Hz = 750Hz


8 0
3 years ago
A car takes 15 minutes to travel along a road that is 20 km long.
iogann1982 [59]

Answer:

C

Explanation:

15. 20

x4. x4

60. 80

80km/h

8 0
3 years ago
Read 2 more answers
https://brainly.com/question/add?entry=1642&task_content=Tania+was+asked+to+describe+the+relashio+of+electrity+and+magnetism
Nat2105 [25]

Answer:

wat

Explanation:

8 0
3 years ago
A 250 kg crate is placed on an adjustable inclined plane. If the crate slides down the incline with an acceleration of 0.7 m/s2
stepladder [879]

Answer:

21.2 degrees

Explanation:

Let gravitational acceleration constant g = 9.81 m/s2 directed downward. We can calculate the g component that is parallel to the 25 degree incline:

gsin25^0 = 9.81sin25^0 = 4.15 m/s^2

This parallel component would produce an acceleration of the block. But since the net acceleration is only 0.7 m/s2, there's a friction acceleration that hinders g parallel. This acceleration can be calculated by

4.15 - a_f = a = 0.7

a_f = 4.15 - 0.7 = 3.45 m/s^2

The force of friction would be

F_f = a_fm = 250 * 3.45 = 816.5 N

Friction is a product of normal force and its coefficient

F_f = \mu N = \mu mgcos25^0 = \mu 250*9.81*cos25^0 = 2222.72 \mu

\mu = F / 2222.72 = 816.5 / 2222.72 = 0.388

For the crate to slide down at constant speed, the net acceleration must be 0. In other words, the parallel g must be the same as acceleration caused by friction. Let this incline angle be α

g sin\alpha = a_f = F_f/m = \frac{\mu N}{m} = \frac{\mu mgcos\alpha}{m} = \mu g cos\alpha

sin\alpha = \mu cos\alpha

\frac{sin \alpha}{cos \alpha} = \mu

tan\alpha = \mu = 0.388

\alpha = tan^{-1} 0.388 = 0.37 rad = 0.37*180/\pi \approx 21.2^0

6 0
4 years ago
The following angles are given in degrees and
Firdavs [7]

bonjour je dis juste un peu de mots aléatoires si vous répondez par "je veux une pizza" cela signifie que vous comprenez et alors et seulement alors je répondrai à votre question
4 0
3 years ago
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