Hello guys could you please help me with this ASAP??

Physics

2 answers:

storchak [24]3 years ago

6 0

Answer:

So that the researchers know how much of the result is a trick of your mind and how much of the result is real.

Explanation:

So first, in order to answer this question we need to know what a placebo is.

Placebo: any treatment that has no active properties, like a sugar pill.

Now we ask ourselves, how could a placebo be something of interest in human studies?

Our brains are amazing things and can connivence themselves many things. Hints the phrase "placebo effect" that is very common in the medical field.

The placebo effect (a positive effect produced by a placebo drug or treatment, which cannot be attributed to the properties of the placebo itself, and must therefore be due to the patient's belief in that treatment) is a really good example as to why they are useful in human studies.

How else could you know was a true effect or just something someone believed would happen anyway?

Lyrx [107]3 years ago

5 0

Placebos are an important part of clinical studies as they provide researchers with a comparison point for new therapies, so they can prove they are safe and effective. They can provide them with the evidence required to apply to regulatory bodies for approval of a new drug.

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Consider a coaxial cable (like the kind that is used to carry a signal to your TV). In this cable, a current I runs in one direc

Ira Lisetskai [31]

Answer:

0 < r < r_exterior B_total = $\frac{\mu_o I}{2\pi r}$

r > r_exterior B_total = 0

Explanation:

The magnetic field created by the wire can be found using Ampere's law

∫ B. ds = μ₀ I

bold indicates vectors and the current is inside the selected path

outside the inner cable

B₁ (2π r) = μ₀ I

B₁ = $\frac{\mu_o I}{2\pi r}$

the direction of this field is found by placing the thumb in the direction of the current and the other fingers closed the direction of the magnetic field which is circular in this case.

For the outer shell

for the case r> r_exterior

B₂ = \frac{\mu_o I}{2\pi r}

This current is in the opposite direction to the current in wire 1, so the magnetic field has a rotation in the opposite direction

for the case r <r_exterior

in this case all the current is outside the point of interest, consequently not as there is no internal current, the field produced is zero

B₂ = 0

Now we can find the field created by each part

0 < r < r_exterior

B_total = B₁

B_total = $\frac{\mu_o I}{2\pi r}$

r > r_exterior