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Lynna [10]
2 years ago
9

Hello guys could you please help me with this ASAP??

Physics
2 answers:
storchak [24]2 years ago
6 0

Answer:

So that the researchers know how much of the result is a trick of your mind and how much of the result is real.

Explanation:

So first, in order to answer this question we need to know what a placebo is.

Placebo: any treatment that has no active properties, like a sugar pill.

Now we ask ourselves, how could a placebo be something of interest in human studies?

Our brains are amazing things and can connivence themselves many things.  Hints the phrase "placebo effect" that is very common in the medical field.

The placebo effect (a positive effect produced by a placebo drug or treatment, which cannot be attributed to the properties of the placebo itself, and must therefore be due to the patient's belief in that treatment) is a really good example as to why they are useful in human studies.

How else could you know was a true effect or just something someone believed would happen anyway?

Lyrx [107]2 years ago
5 0
Placebos are an important part of clinical studies as they provide researchers with a comparison point for new therapies, so they can prove they are safe and effective. They can provide them with the evidence required to apply to regulatory bodies for approval of a new drug.
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3 years ago
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When a man walks across the carpet and reaches for the door knob, why does he get shocked? doorknob Question 3 options: There is
Mumz [18]

The imbalance of electric charges within or on the surface of a material or between materials is known as static electricity. When you grab a doorknob, electrons jump from your hand to the knob .which conducts electricity, giving you a shock.

<h3>What is static electricity?</h3>

The imbalance of electric charges within or on the surface of a material or between materials is known as static electricity.

The charge will persist until it can be moved away by an electric current or an electrical discharge.

when we walk on the carpet with socks our feet slide electrons off the carpet.  it leads to leaving you with a slightly negative static charge.

When you grab a doorknob electrons jump from your hand to the knob which conducts electricity giving you a shock.

Due to the static electricity jump from your hand to the knob .which conducts electricity giving you a shock.

To know more about static electricity refer to the link ;

brainly.com/question/821085

3 0
2 years ago
A clay vase on a potter's wheel experiences an angular acceleration of 5.69 rad/s2 due to the application of a 16.0-n m net torq
Digiron [165]
The equivalent of the Newton's second law for rotational motions is:
\tau = I \alpha
where
\tau is the net torque acting on the object
I is its moment of inertia
\alpha is the angular acceleration of the object.

Re-arranging the formula, we get
I= \frac{\tau}{\alpha}
and since we know the net torque acting on the (vase+potter's wheel) system, \tau=16.0 Nm, and its angular acceleration, \alpha = 5.69 rad/s^2, we can calculate the moment of inertia of the system:
I= \frac{\tau}{\alpha}= \frac{16.0 Nm}{5.69 rad/s^2} =2.81 kg m^2
8 0
3 years ago
Wile E. Coyote is holding a "HEAVY DUTY ACME™ ANVIL" on a cliff that is 40.0 meters high. The Roadrunner (beep-beep), who is 1.0
Mariana [72]

Answer:

53.8

Explanation: I plugged it on the formula

3 0
2 years ago
A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it
mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm

r = 0.145\ cm = 0.145\times 10^{-2}\ m

Charge ,

Q = 30.0\ pC=30\times 10^{-12}

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}

Where,  

V= Electric potential,  

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge  

r = Radius  

Substituting the values we get

V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}

V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0
3 years ago
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