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2 years ago

Hello guys could you please help me with this ASAP??

Physics

2 answers:

storchak [24]2 years ago

6 0

Answer:

So that the researchers know how much of the result is a trick of your mind and how much of the result is real.

Explanation:

So first, in order to answer this question we need to know what a placebo is.

Placebo: any treatment that has no active properties, like a sugar pill.

Now we ask ourselves, how could a placebo be something of interest in human studies?

Our brains are amazing things and can connivence themselves many things. Hints the phrase "placebo effect" that is very common in the medical field.

The placebo effect (a positive effect produced by a placebo drug or treatment, which cannot be attributed to the properties of the placebo itself, and must therefore be due to the patient's belief in that treatment) is a really good example as to why they are useful in human studies.

How else could you know was a true effect or just something someone believed would happen anyway?

Lyrx [107]2 years ago

5 0

Placebos are an important part of clinical studies as they provide researchers with a comparison point for new therapies, so they can prove they are safe and effective. They can provide them with the evidence required to apply to regulatory bodies for approval of a new drug.

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Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The

Greeley [361]

Answer:

I = 215.76 A

Explanation:

The direction of magnetic field produced by conductor 1 on the location of conductor 2 is towards left. Based on Right Hand Rule -1 and taking figure 21.3 as reference, the direction of force Fm due to magnetic field produced at C_2 is shown above. The force Fm balances the weight of conductor 2.

Fm = u_o*I^2*L/2*π*d

where I is the current in each rod, d = 0.0082 m is the distance 27rId

between each, L = 0.85 m is the length of each rod.

Fm = 4π*10^-7*I^2*1.1/2*π*0.0083

The mass of each rod is m = 0.0276 kg

F_m = mg

4π*10^-7*I^2*1.1/2*π*0.0083=0.0276*9.8

I = 215.76 A

note:

mathematical calculation maybe wrong or having little bit error but the method is perfectly fine

5 0

3 years ago

I got the correct answer, but I don't know what I did. Why is the answer E?

MariettaO [177]

Explanation:

Displacement is the straight line distance from the starting position to the final position.

Person X walks halfway around circle. So her displacement is 100 m.

Person Y walks 3/4 of the way around. So his displacement is 50√2 m ≈ 70.7 m.

Person Z walks completely around the circle, so their displacement is 0 m.

Therefore:

Z < Y < X

6 0

2 years ago

Many scientists accept a theory about the origin of the universe, called the big bang theory. describe at least one piece of sci

alexandr402 [8]

Red shift is one piece of observational evidence which supports the big bang theory. The fact that galaxies are moving away from us means that the universe was once much smaller, supporting the big bang theory which states that all the matter in the universe once occupied a single point with infinite density.

3 0

2 years ago

A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net = 4.444 N

Dmitriy789 [7]

Answer:

The value of third charge is 0.8μC.

Explanation:

Given that.

Magnitude of net force=4.444 N

According to figure,

Suppose, First charge = 2.4 μC

Second charge = 6.2 μC

Distance r₁ = 9.8 cm

Distance r₂ = 2.1 cm

We need to calculate the value of r

Using Pythagorean theorem

$r=\sqrt{(r_{1})^2+(r_{2})^2}$

Put the value into the formula

$r=\sqrt{(9.8)^2+(2.1)^2}$

$r=10.02\ cm$

We need to calculate the force

Using formula of force

$F_{12}=\dfrac{kq_{1}q_{2}}{(r)^2}$

Force F₁₂,

$F_{12}=\dfrac{9\times10^{9}\times2.4\times10^{-6}\times6.2\times10^{-6}}{(10.02\times10^{-2})^2}$

$F_{12}=13.33\ N$

$F_{21}=-13.33\ N$

Force F₂₃,

$F_{23}=\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(10.02)^2}$

We need to calculate the value of third charge

$F_{net}=F_{21}+F_{23}$

$4.444=-13.33+\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(5.01)^2}$

$q_{3}=\dfrac{(4.444+13.33)\times(5.01\times10^{-2})^2}{9\times10^{9}\times6.2\times10^{-6}}$

$q_{3}=7.99\times10^{-7}\ C$

$q_{3}=0.8\times10^{-6}\ C$

Hence, The value of third charge is 0.8μC.

4 0

2 years ago

A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is

tester [92]

To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,

Frequency $= f = 562Hz$