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e-lub [12.9K]
1 year ago
8

A 5.0-kg object is suspended by a string from the ceiling of an elevator that is accelerating downward at a rate of 2.6 m/s 2. W

hat is the tension in the string
Physics
1 answer:
Tcecarenko [31]1 year ago
8 0

The tension in the string is 36 N.

To find the answer, we need to know about pseudo acceleration.

<h3>What's pseudo acceleration?</h3>
  • When an object is placed on a vehicle, it experiences a pseudo acceleration in the opposite direction of the motion of the vehicle.
  • Magnitude of the pseudo acceleration is same as that of the acceleration of vehicle.
<h3>What's the pseudo acceleration of a mass suspended in a lift that's moving downward with an acceleration of 2.6 m/s²?</h3>
  • Here, the acceleration of the lift is 2.6m/s², so the mass suspended by a string inside it will feel a pseudo acceleration of 2.6m/s² upward.
  • So the effective acceleration of the mass = acceleration due to gravity - pseudo acceleration = 9.8 - 2.6 = 7.2 m/s²
<h3>What's the tension of the string suspending the mass?</h3>

Tension of the string= mass × effective acceleration

= 5 × 7.2 = 36 N

Thus, we can conclude that the tension in the string is 36 N.

Learn more about the pseudo acceleration here:

brainly.com/question/26644944

#SPJ4

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Ice floats in water because it is______ than matter
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A 2kg block is sitting on a hinged ramp such that you can increase the angle of the incline. The coefficient of static friction
MariettaO [177]

Answer:

θ = 33.8

a = 3.42 m/s²

Explanation:

given data

mass m = 2 kg  

coefficient of static friction μs = 0.67

coefficient of kinetic friction μk = 0.25

solution

when block start slide

N = mg cosθ    .............1

fs = mg sinθ   ...............2

now we divide equation 2 by equation 1 we get

\frsc{fs}{N} = \frac{sin \theta }{cos \theta }

\frac{\mu s N }{N}  = tanθ

put here value we get

tan θ = 0.67

θ = 33.8

and

when block will slide  then we apply newton 2nd law

mg sinθ - fk = ma    ...............3

here fk = μk N = μk mg cosθ

so from equation 3 we get

mg sinθ -  μk mg cosθ = ma

so a will be

a = (sinθ - μk cosθ)g

put here value and we get

a = (sin33.8 - 0.25 cos33.8) 9.8

a = 3.42 m/s²

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Identify one type of electromagnetic energy that has a shorter wavelength than green light
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An 10 kg mass has an applied force of magnitude 69N acting on it pushing it to move in the positive x-direction. The mass is on
Oduvanchick [21]

The net force on the mass in the vertical direction is

∑ <em>F</em> = <em>n</em> - <em>w</em> = 0

and the net horizontal force is

∑ <em>F</em> = <em>A</em> - <em>f</em> = <em>ma</em>

where

<em>n</em> = magnitude of the normal force

<em>w</em> = <em>mg</em> = weight of the mass

<em>m</em> = 10 kg, mass of the … uh, mass

<em>g</em> = 9.8 m/s², mag. of acceleration due to gravity

<em>A</em> = 69 N, mag. of the applied force

<em>f</em> = mag. of kinetic friction

From the first equation, we get

<em>n</em> = <em>mg</em> = (10 kg) (9.8 m/s²) = 98 N

Then the friction force has magnitude

<em>f</em> = <em>µ</em> <em>n</em> = 0.5 (98 N) = 49 N

Solve the mass's acceleration in the second equation:

69 N - 49 N = (10 kg) <em>a</em>

<em>a</em> = (20 N) / (10 kg) = 2.0 m/s²

in the positive <em>x</em> direction.

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