1. 12.75 J
Assuming that the force applied is parallel to the ramp, so it is parallel to the displacement of the cart, the work done by the force is
where
F = 15 N is the magnitude of the force
d = 85 cm = 0.85 m is the displacement of the cart
Substituting in the formula, we get
2. 10.6 N
In this part, the cart reaches the same vertical height as in part A. This means that the same work has been done (because the work done is equal to the gain in gravitational potential energy of the object: but if the vertical height reached is the same, then the gain in gravitational potential energy is the same, so the work done must be the same).
Therefore, the work done is
However, in this case the displacement is
d = 120 cm = 1.20 m
Therefore, the magnitude of the force in this case is
Answer:
Option C
Explanation:
From the question we are told that:
Mass 
Radius 
Time 
Generally the equation for Tension is mathematically given by
Therefore
, toward the center of the circle
Option C
Answer:
Let one side = Let the other side= Let area = Let perimeter= Now substitute into area formula
Explanation:
120/60= 2m per s
220/55= 4m per s
720/80= 9m per s
Fastest run: 3rd run
Speed: 9m per s
Slowest: 1st run
Speed: 2m per s
Answer:
Displacement.
Explanation:
The change in between the starting position (initial position) and your final position is the amount of distance you <em>actually </em>traveled.
For example, you can use a triangle. The distance you travel for side length a & b is equal to the distance you travel on side c (the hypotenuse). You are pretty much solving for the hypotenuse in this case, or the displacement.
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