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arsen [322]
4 years ago
8

A block of weight w sits on a frictionless inclined plane, which makes an angle theta with respect to the horizontal, as shown.

A force of magnitude F applied parallel to the incline, pulls the block up the plane at constant speed. The block moves a distance L up the incline. The block does not stop after moving this distance but continues to move with constant speed. What is the total work Wtot done on the block by all forces? (Include only the work done after the block has started moving, not the work needed to start the block moving from rest.) What is Wg , the work done on the block by the force of gravity as the block moves a distance L up the incline? What is Wf the work done on the block by the applied force F as the block moves a distance L up the incline? What is Wnormal , the work done on the block by the normal force as the block moves a distance L up the inclined plane?
Physics
1 answer:
zavuch27 [327]4 years ago
6 0

Answer:

a.

Explanation:

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Answer:

Use Fc centripetal force as positive and W the weight as negative

N = m v^2 / R + m g

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v^2 = (995 - 57 * 9.8) 42.7 / 57 = 327 m^2/s^2

v = 18.1 m/s

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Which type of force can be in the same it opposite direction?
LuckyWell [14K]

Answer:

C) unbalanced

Explanation:

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4 0
3 years ago
The tonga trench in the pacific ocean is 36,000 feet deep. assuming that sea water has an average density of 1.04 g/cm3, calcula
MakcuM [25]
1110 atm    

Let's start by calculating how many cm deep is 36,000 feet. 

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 Now calculate how much a column of water 1 cm square and that tall would mass. 

 1097280 cm * 1.04 g/cm^3 = 1141171.2 g/cm^2   

 We now have a number using g/cm^2 as it's unit and we desire a unit of Pascals ( kg/(m*s^2) ).  

 It's pretty obvious how to convert from g to kg. But going from cm^2 to m is problematical. Additionally, the s^2 value is also a problem since nothing in the value has seconds as an unit. This indicates that a value has been omitted. We need something with a s^2 term and an additional length term. And what pops into mind is gravitational acceleration which is m/s^2. So let's multiply that in after getting that cm^2 term into m^2 and the g term into kg.   

 1141171.2 g/cm^2 / 1000 g/kg * 100 cm/m * 100 cm/m = 11411712 kg/m^2 

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 111834777.6 Pa / 1.01x10^5 Pa/atm = 1107.2750 atm   

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8 0
3 years ago
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3 years ago
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