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fomenos
3 years ago
7

Kinetic energy help! (#4)

Physics
1 answer:
zloy xaker [14]3 years ago
5 0
For problem number 4:

It says it is moving 10% of the speed of light. The speed of light is 3*10^8 m/s.
So:

KE = 0.5mv^2 = 0.5*(1.67*10^-27kg)(3*10^8*0.1)^2
KE = 7.515*10^-13 J

Problem 5:
W = ΔKE
Since it is initially at rest, we can simplify W = KE. KE = 0.5mv^2

3.4*10^-16J = 0.5(9.11*10^-31)v^2
v = 27320916.74 m/s


Problem 6:
mgh = 0.5mv^2
(0.1kg)*(10m/s^2)*(16m) = 0.5(0.1kg)v^2
v = 17.8885m/2

Did this really quickly, so might not be accurate!
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Explanation:

Hope it will help u

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3 years ago
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They given vectors are parallel vectors because they have same direction.

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3 years ago
An arrow is shot straight up in the air at an initial speed of 15 m/s. After how much time is the arrow heading downward at a sp
Greeley [361]

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2.35 seconds

Explanation:

Remark

This is a question where direction matters.  Let us call down + and up minus. It won't matter. The answer will be the same.

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Givens

a = 9.8 m/s^2

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7 0
3 years ago
A stuntman is being pulled along a rough road at a constant velocity by a cable attached to a moving truck. The cable is paralle
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6 0
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Answer:

Option 3 and 6

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4 0
3 years ago
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