Answer: you can use a strainer
Explanation:
<u>Answer:</u>
<u>When an alkyl benzene is heated with strong oxidizing asgents like acidic or alkline KMnO4</u>
<u> or acidified K2Cr2O7</u>
<u>, etc. gives aromatic carboxyllic acid. The alkyl side chain gets oxidised to −COOH</u>
<u> group irrespective of the size of the chain.</u>
Explanation:
Ok so all are in the alkali family also they are all metals and in group 1 but I think the one that might reacts quickest is Li because it has less AMU
<span>The benefit of the space shuttle is that A. it's reusable. This means that after this shuttle has been used for one mission, it can be use for numerous other missions again, until it gets broken and cannot run anymore. B is incorrect because it cannot land - it is only there to observe. C is incorrect because more than one person can fit. D is incorrect because it doesn't orbit the Earth permanently - it returns at one point.</span>
This is a freezing point depression problem, so it will use the equation:
ΔT = i Kf<span> m
</span>
i = 1 (naphthalene does not dissociate further when dissolved)
Kf = 7.10 C/m (a constant for paradichlorobenzene, which you'd be given)
m = moles of solute / kg of solvent; moles of solute = 4.78 / 128.2 = 0.0373; kg of solvent = 0.032; m = 0.0373 / 0.032 = <span>1.166m
</span>ΔT = 1 x 7.10 x 1.166 = 8.279 C
This means the normal freezing point of pure paradichlorobenzene is decreased by 8.279 C; the normal freezing point (again, something you'd be given) is 53.5 C, so the new freezing point would be 53.5 - 8.279 = 45.221 C.