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suter [353]
3 years ago
15

A 5.0 g sample of aluminum with a specific heat of 0.90 J/(g °C) was heated from 22.1°C to 32.1°C. How much heat, to the nearest

joule, did the aluminum gain?
Chemistry
1 answer:
mina [271]3 years ago
7 0
Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
Heat = 5(0.90)(32.1 - 22.1)
Heat = 45 J energy gained
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Answer:

NaOCl + H2O → HOCl + NaOH

so the mole fraction is = moles of NaOCl/(moles of NaOCl+moles of H2O)

so for 1.35 NaOCl it will require 1.35 moleof H2O

mole fraction = 1.35/(1.35+1.35)

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is it correct i d ek but i tried :)

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Answer:

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