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suter [353]
3 years ago
15

A 5.0 g sample of aluminum with a specific heat of 0.90 J/(g °C) was heated from 22.1°C to 32.1°C. How much heat, to the nearest

joule, did the aluminum gain?
Chemistry
1 answer:
mina [271]3 years ago
7 0
Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
Heat = 5(0.90)(32.1 - 22.1)
Heat = 45 J energy gained
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We can thus, write the above equation as:

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The above equation is called the general gas equation.

Step 2:

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Initial pressure (P1) = 0.974 atm.

Final temperature (T2) = 15.0°C = 15.0°C + 273 = 288K

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295x0.993xV2 = 0.974x27.5x288

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V2 = (0.974x27.5x288)/(295x0.993)

V2 = 26.3 mL

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