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suter [353]
3 years ago
15

A 5.0 g sample of aluminum with a specific heat of 0.90 J/(g °C) was heated from 22.1°C to 32.1°C. How much heat, to the nearest

joule, did the aluminum gain?
Chemistry
1 answer:
mina [271]3 years ago
7 0
Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
Heat = 5(0.90)(32.1 - 22.1)
Heat = 45 J energy gained
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Considering the Charles's law, the sample of carbon dioxide gas will occupy 308.72 mL.

<h3>Charles's law</h3>

Charles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

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\frac{V}{T} =k

Considering an initial state 1 and a final state 2, it is fulfilled:

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<h3>Final volume in this case</h3>

In this case, you know:

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Replacing in Charles's law:

\frac{250 mL}{298 K} =\frac{V2}{368 K}

Solving:

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<u><em>V2= 308.72 mL</em></u>

Finally, the sample of carbon dioxide gas will occupy 308.72 mL.

Learn more about Charles's law:

brainly.com/question/4147359

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