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lora16 [44]
3 years ago
9

Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica?

Physics
2 answers:
balandron [24]3 years ago
8 0

Answer:

The normal force that the wall exerts on the ball.

Explanation:

Erica throws a tennis ball against a wall, and it bounces back. Here Newton's third law of motion follows. When the ball hits the wall, the wall will also exert an equal and opposite force on the ball as per third law. The opposite force that wall exert on ball is normal force which is responsible for sending the ball back to Erica.

Hence, the force is normal force exerted by the wall on the ball.

matrenka [14]3 years ago
6 0
Kinetic energy is responsible for this

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If 4 x 10^21 electrons pass through a wire connected to a 15 ohm resistor in 3 s, how much electric
sammy [17]

Answer:

1.) Current = 213.33A

2.) Potential difference = 3200 V

Explanation:

Given that

Number of electrons n = 4 x 10^21 electrons

Resistance R = 15 ohm

Time t = 3 s

From the definition of current ;

Current is the rate of flow of changes. That is,

Current I = Q/t

Where

Q = 4 × 10^21 × 1.6 × 10^-19

Q = 460C

Current I = 460/3

Current I = 213.33 A

Using Ohms law which state that

V = IR

Substitute the resistance R and current I into the formula above

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3 years ago
If the spring constant is 10 N/m and the spring is stretched 1 m, what is the Force?
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Answer:

10N

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F = kx

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6 0
2 years ago
When is the next total solar eclipse in north america
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5 0
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A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away
Tatiana [17]

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length,  the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

<h3>What is the electric field intensity 20cm away from the rod along its perpendicular bisector?</h3>

Generally, the equation for the  initial electric field intensity   is mathematically given as

dEp=\int{kd/r}cosd\theta

Therefore

e1=kd/r{sin\theta2+sinR1}

Hence

E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2

E1=B*9*10^{13})/(10*110)*\sqrt{2}

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

Read more about Electric field

brainly.com/question/9383604

6 0
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