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arlik [135]
3 years ago
6

The magnetic field a distance 2 cm from a long straight current-carrying wire is 2 × 10–5 t. the current in the wire is:

Physics
1 answer:
Sliva [168]3 years ago
6 0

Current in the wire = 2 A

Explanation:

the magnetic field is given by

B= \frac{\mu i}{2\pi r}

μo= 4π x 10⁻⁷ Tm/A

i= current

r=0.02 m

B = magnetic field= 2 x 10⁻⁵ T

2 x 10⁻⁵= (4π x 10⁻⁷)(i) / (2π*0.02)

i=2 A

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A 7.0-kilogram cart, A, and a 3.0-kilogram cart, B, are initially held together at rest on a horizontal, frictionless surface. W
7nadin3 [17]
For this problem, we use the conservation of momentum as a solution. Since momentum is mass times velocity, then,

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
where
v₁ and v₂ are initial velocities of cart A and B, respectively
v₁' and v₂' are final velocities of cart A and B, respectively
m₁ and m₂ are masses of cart A and B, respectively

(7 kg)(0 m/s) + (3 kg)(0 m/s) = (7 kg)(v₁') + (3 kg)(6 m/s)
Solving for v₁',
v₁' = -2.57 m/s

<em>Therefore, the speed of cart A is at 2.57 m/s at the direction opposite of cart B.</em>
7 0
4 years ago
A 4kg block slides freely across a rough surface such that the block slows down with an acceleration of −1.25 m/s2 . What is the
Sophie [7]

Answer:

The coefficient of kinetic friction between the block and the surface is 0.127.

Explanation:

Given that,

The mass of a block, m = 4 kg

The acceleration of the block, a = -1.25 m/s²

We need to find the coefficient of kinetic friction between the block and the surface. The force of friction is given by :

F=\mu mg\\\\ma=\mu mg\\\\\mu=\dfrac{a}{g}\\\\\mu=\dfrac{1.25}{9.8}\\\\\mu=0.127

So, the coefficient of kinetic friction between the block and the surface is 0.127.

6 0
3 years ago
I SEE YOU....STOO CHEATING!!!!!!
professor190 [17]
BAHHAHAJA WHY IS THIS SO FUNNY
4 0
3 years ago
4. Identify Problems A student is describing a longitudinal wave in his notebook. He
andrew11 [14]

Answer:

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Explanation:

If he writes down "The distance between crests is 3 cm." 

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Longitudinal waves are waves in which the displacement of the medium is in the same direction as, or parallel to, the direction of propagation of the wave. While

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3 0
3 years ago
A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hang
Romashka-Z-Leto [24]

Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/s^{2}. The correct answer is 4.90 m/s^{2}

Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.

Let M = 1kg and m = 3 kg

Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.

When the mass is released, the cart accelerates to the right can be calculated  from Newton' second law of motion. That is,

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1(9.8 + a) = 3( 9.8 - a)

9.8 +a = 29.4 - 3a

collect the like terms

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Therefore, the cart accelerates to the right with a magnitude of 4.9 m/s^{2}. The correct answer is 4.90 m/s^{2}

Learn more about dynamics here: brainly.com/question/24994188

5 0
3 years ago
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