Choices 'B'; and 'D' both begin with the correct words.
But they should end with the equation
R = V / I
Answer:
4 times greater
Explanation:
<u>Step 1:</u> Calculate light-collecting area of a 20-meter telescope (A₁) by using area of a circle.
Area of circle = π*r² =
Where d is the diameter of the circle = 20-m


A₁ = 314.2 m²
<u>Step 2:</u> Calculate light-collecting area of a 10-meter Keck telescope (A₂)

Where d is the diameter of the circle = 10-m

A₂ = 78.55 m²
<u>Step 3</u>: divide A₁ by A₂

= 4
Therefor, the 20-meter telescope light-collecting area would be 4 times greater than that of the 10-meter Keck telescope.
Answer:
(a) the deceleration of the player is -80.36 m/s²
(b) the time the collision last is 0.093 s
Explanation:
Given;
Initial velocity of the football player, u = 7.50 m/s
Final velocity of the football player, v = 0
distance traveled = compression of the pad, s = 0.35 m
Part (a) the deceleration of the player
v² = u² + 2as
0 = 7.5² + (2 x 0.35)a
0 = 56.25 + 0.7a
- 56.25 = 0.7a
a = -56.25 / 0.7
a = -80.36 m/s²
Part (b) the time the collision last
v = u + at
t = (v - u)/a
t = (0 - 7.5)/ -80.36
t = - 7.5 / -80.36
t = 0.093 s
Answer and Explanation:
Most of the distances in the galaxy are measured in light years instead of meter because the distances in galaxy are very large and it is very difficult to measure in meters and light year is the largest unit of distance so it is very easy to measure large distances in light year so we prefer light year instead of meters for measuring distances in galaxy.
Complete Question
The complete question(reference (chegg)) is shown on the first uploaded image
Answer:
The magnitude of the resultant force is 
The direction of the resultant force is
from the horizontal plane
Explanation:
Generally when resolving force, if the force (F )is moving toward the angle then the resolve force will be
while if the force is moving away from the angle then the resolved force is 
Now from the diagram let resolve the forces to their horizontal component
So


Now resolving these force into their vertical component can be mathematically evaluated as


Now the resultant force is mathematically evaluated as

substituting values


The direction of the resultant force is evaluated as
![\theta = tan^{-1}[\frac{F_y}{F_x} ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7BF_y%7D%7BF_x%7D%20%5D)
substituting values
![\theta = tan^{-1}[\frac{ 14.3}{199.128} ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7B%2014.3%7D%7B199.128%7D%20%5D)
from the horizontal plane