The centripetal force acting on the rider is much greater if the roller coaster has a circular loop, rather than oval. This is because the change in direction is much sharper throughout the loop, causing the rider to experience a much more intense G-Force throughout the loop.
A teardrop loop features a more gradual change of direction: the cart spends time moving upward, briefly changes direction, and spends the rest of the time moving downward and flattening to a horizontal path. This means the riders experience the majority of the force on the way down as the car levels out, rather than an intense G-force throughout the ride.
The Atwood's machine is in motion starting from rest, then Vf = Vo + a(t).
<span>Final Velocity is given as 6.7 m/s and the time is 1.9 s thus 6.7= 0+ a(1.9) </span>
<span>then a = 6.7/1.9 = 3.526 m/s². </span>
<span>The Atwood's Machine also has the formula d= distance = 1/2a(t²) </span>
<span>distance given is 6.365 m , then 6.365 = 1/2 a (1.9)², </span>
<span>a = 3.526 m/s² the same acceleration. </span>
<span>a= g(m1-m2) / m1+m2) </span>
<span>m1a + m2a = m1g - m2g </span>
<span>m1a - m1g = -m2g - m2a </span>
<span>3.526 m1 - 9.81 m1 = -9.81m2 - 3.526 m2 </span>
<span>-6.28 m1 = -13.34 m2 </span>
<span>0.47 m1= m2 </span>
<span>if 24J = 1/2mv² </span>
<span>then 24J = 1/2 m1 ( 6.7)² </span>
<span>48/ 44.89 = m1 </span>
<span>1.069 kg = m1 , then </span>
<span>0.47(1.069) = m2 </span>
<span>0.503 kg = m2</span>
Answer with explanation:
The Normalization Principle states that
Given
Thus solving the integral we get
The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below
Applying the limits and solving for A we get
![I=\frac{1}{k}[\frac{1}{e^{kx}}-\frac{x}{e^{kx}}]_{0}^{+\infty }\\\\I=-\frac{1}{k}\\\\\therefore A=-k](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7Bk%7D%5B%5Cfrac%7B1%7D%7Be%5E%7Bkx%7D%7D-%5Cfrac%7Bx%7D%7Be%5E%7Bkx%7D%7D%5D_%7B0%7D%5E%7B%2B%5Cinfty%20%7D%5C%5C%5C%5CI%3D-%5Cfrac%7B1%7D%7Bk%7D%5C%5C%5C%5C%5Ctherefore%20A%3D-k)
Answer:
4186 Joules
Explanation:
The specific heat capacity of a substance is defined as the amount of heat needed to raise the temperature of 1 kg of the substance by 1 Kelvin. In formula,
where
Q is the amiunt of heat needed
m = 1 kg is the mass
is the variation of temperature of the substance
For water, the specific heat capacity is 
. This means that the heat energy required to raise 1 kg of water by 1 K is exactly 4186 J.
At its peak height, the hotdog will have no vertical velocity, so that
