Answer:
The acceleration is 8 m/s²
Explanation:
The given parameters are;
The initial velocity, u = 2 m/s
The final velocity, v = 6 m/s
The distance the acceleration took place, s = 2 m
The acceleration, a, can be found from the following kinematic equation;
v² = u² + 2·a·s
By substituting the values, we have;
6² = 2² + 2 × a × 2
6² - 2² = 2 × a × 2
32 = 4·a
a = 32/4 = 8 m/s²
The acceleration, a, of the given motion = 8 m/s².
Explanation:
Given: Initial Velocity=0
Final Velocity= 20 m/s
Time= 4 s
Accleration: Unknowns
Use kinematic equation
so a = 5 m/s^2
Either of them is. 1/(the other one). That's 'C' .
By putting to much weight on it our body causing it to hurt or fall hope this helps
Explanation:
At maximum height, the vertical component of a ball's speed is 0. So the net speed is equal to whatever the horizontal component of the ball is. If the ball is launched straight up, the speed at the highest point is simply 0.
