The molality of solution prepared by mixing 25.5 mL of and 387 mL of is .
Further Explanation:
Different concentration terms are utilized in determining the concentration of various solutions. Some of the most commonly used terms are written below.
1. Molarity (M)
2. Mole fraction (X)
3. Molality (m)
4. Parts per million (ppm)
5. Mass percent ((w/w) %)
6. Volume percent ((v/v) %)
Molality is one of the concentration terms used very often in solutions. It is defined as moles of solute divided by the mass of solvent in kilograms. The formula to calculate molality of solution is as follows:
…… (1)
The formula to calculate the density of component is as follows:
…… (2)
Rearrange equation (2) to calculate mass of component.
…… (3)
Substitute 25.5 mL for volume of component and 0.792 g/mL for density of component in equation (3) to calculate mass of .
Substitute 387 mL for volume of component and 0.811 g/mL for density of component in equation (3) to calculate mass of .
The formula to calculate moles of is as follows:
…… (4)
Substitute 20.196 g for mass of and 32.04 g/mol for molar mass of in equation (4).
Substitute 0.6303 mol for moles of solute and 0.3139 kg for mass of solvent in equation (1) to calculate molality of given solution.
Learn more:
- Calculation of volume of gas: brainly.com/question/3636135
- Determine how many moles of water produce: brainly.com/question/1405182
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: concentration, concentration terms, 2.01 m, molality, moles, mass, 0.3139 kg, CH3OH, CH3CH2CH2OH, 0.6303 mol.