Answer: Force F will be one-sixteenth of the new force when the charges are doubled and distance halved
Explanation:
Let the charges be q1 and q2 and the distance between the charges be 'd'
Mathematical representation of coulombs law will be;
F1=kq1q2/d²...(1)
Where k is the electrostatic constant.
If q1 and q2 is doubled and the distance halved, we will have;
F2 = k(2q1)(2q2)/(d/2)²
F2 = 4kq1q2/(d²/4)
F2 = 16kq1q2/d²...(2)
Dividing equation 1 by 2
F1/F2 = kq1q2/d² ÷ 16kq1q2/d²
F1/F2 = kq1q2/d² × d²/16kq1q2
F1/F2 = 1/16
F1 = 1/16F2
This shows that the force F will be one-sixteenth of the new force when the charges are doubled and distance halved
Increase in wavelength will cause decrease in frequency. When wavelength doubles, the frequency of the wave will reduce to half of its value.
<h3>
WAVE SPEED</h3>
The wave speed is the product of wave frequency and its wavelength.
v = f⋅λ
For example, if a wave has a frequency of 120 Hz and a wavelength of 5m, it would have a speed of 600 m/s.
if the wavelength is increased to 10m but the speed stays the same at 600 m/s. That is,
λ = 10m
v = 600 m/s
v = f⋅λ
Substitute f and v into the formula
600 = 10f
f = 600 / 10
f = 60 m
The frequency of the wave is reduced to half of its value.
Learn more about wave speed here: brainly.com/question/2847127
Wavelength and frequency have a reciprocal relationship. If one doubles, the other halves.
