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sveticcg [70]
3 years ago
9

What is the mass of an object if the force of 17 n causes it to accelerate at 1.5 m/s/s?

Physics
1 answer:
nikklg [1K]3 years ago
3 0

newton's second law results in force = mass times acceleration

17 = mass x 1.5

mass = 17/1.5

=17/3x2 = just under 12


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A proton is released from rest inside a region of constant, uniform electric field E1 pointing due North. 32.3 seconds after it
NARA [144]

Answer:

E₂ / E₁ = 521.64 / 5.95 =87.67

Explanation:

Let d be the distance covered inside electric field . Lt q be the magnitude of charge.

Force under field E₁ = q E₁

acceleration = qE₁/ m

d = 1/2 a t²

d = .5 ( qE₁ / m) x 32.3²

d = 521.64 ( qE₁ / m)

Similarly for return journey,

d = .5 x ( qE₂ / m) x 3.45²

d = 5.95x( qE₂ / m)

521.64 ( qE₁ / m) = 5.95x( qE₂ / m)

E₂ / E₁ = 521.64 / 5.95 =87.67

8 0
3 years ago
In the presence of a nucleus the energy of a y-ray photon can be converted into an electron-positron pair. Calculate the minimum
Vlada [557]

Answer:

Explanation:

mass of electron in amu = .000549

mass of electron = mass of proton

total mass of electron and proton = 2 x1.098 x 10⁻³ = 2.196 x 10⁻³ amu

1 amu = 931 x 10⁶ eV

2.196 X 10⁻³ amu = 2.196 x 931 x 10³ eV

= 2.044 X 10⁶ eV.

= 2044 X 10³ ev

So minimum energy required = 2044 x 10³ eV.

Wavelength of photon required = 12375/2044 x 10³ A

= 6.054 X 10⁻³A. =6.054 X 10⁻¹³ m

frequency of photon  = 3 x 10⁸/6.054x 10⁻¹³

= .4955 x 10¹⁶Hz.

= 4.955 x 10¹⁵ Hz

3 0
4 years ago
Monochromatic light falls on a metal surface that has a work function of 6.7 x 10-19 J. Each photon has an energy of 8.0 x 10-19
alina1380 [7]

Answer:

Correct answer: (a) Ekmax =  1.3 · 10⁻¹⁹ J, (b) ε = 5 eV, (c) f = 1.21 · 10¹⁵ Hz

Explanation:

Given:

photon energy  ε = 8 · 10⁻¹⁹ J

work function for metal  Wf = 6.7 · 10⁻¹⁹ J

(a) Ekmax = ?

The Einstein equation for photo effect is:

ε = Wf + Ekmax  ⇒ Ekmax = ε - Wf

Ekmax = 8 · 10⁻¹⁹ - 6.7 · 10⁻¹⁹ = 1.3 · 10⁻¹⁹ J

Ekmax =  1.3 · 10⁻¹⁹ J

(b)  ε = ? eV

the relationship between 1 eV and 1 J is:

1 eV = 1.6 · 10⁻¹⁹ J

so the energy of one photon in eV equals:

ε = 8 · 10⁻¹⁹ J = 8 · 10⁻¹⁹ / 1.6 · 10⁻¹⁹ eV = 5 eV

ε = 5 eV

(c)  f = ?

the energy of a single photon is calculated according to the formula:

ε = h · f  

where is:

h = 6.62 ·  10⁻³⁴ J s    plank constant

and f  frequency of each photon (electromagnetic radiation)

f = ε / h = 8 · 10⁻¹⁹ J / 6.62 ·  10⁻³⁴ J s = 1.21 · 10¹⁵ s⁻¹ =  1.21 · 10¹⁵ Hz

f = 1.21 · 10¹⁵ Hz

God is with you!!!

8 0
3 years ago
Question 4 of 10
Nataly_w [17]

Answer:

Normative

Explanation:

It is normal occurance but not unnatural

3 0
3 years ago
Physics help!!<br><br> Thanks if you do
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