Answer:
4 m/s
Explanation:
Momentum is conserved.
m₁ v₁ + m₂ v₂ = (m₁ + m₂) v
(50)(5) + (20)(1.5) = (50 + 20) v
v = 4
The final velocity is 4 m/s.
Answer:
12.3 m/s
Explanation:
The Doppler equation describes how sound frequency depends on relative velocities:
fr = fs (c + vr)/(c + vs),
where fr is the frequency heard by the receiver,
fs is the frequency emitted at the source,
c is the speed of sound,
vr is the velocity of the receiver,
and vs is the velocity of the source.
Note: vr is positive if the receiver is moving towards the source, negative if away.
Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.
Given:
fs = 894 Hz
fr = 926 Hz
c = 343 m/s
vs = 0 m/s
Find: vr
926 = 894 (343 + vr) / (343 + 0)
vr = 12.3
The speed of the car is 12.3 m/s.
Let h = distance (m) to the water surface.
Initial velocity, u = 0 (because the stone was dropped).
Use the formula
h = ut + (1/2)gt^2
where g = 9.8 m/s^2 (acc. due to graity)
t = time (s)
h = (1/2)*(9.8)*(3^2) = 44.1 m
The northern lights are shafts or curtains of colorful light that occasionally appear in the night sky. They are one of the numerous astronomical phenomena known as polar lights (aurora Polaris).This phenomenon may be observed in mars.
Earth's magnetic field directs electrons and protons from the sun to the poles, where they excite atmospheric gas molecules and cause them to glow, resulting in the aurora borealis and aurora australis, two nocturnal light displays. You might refer to it as the aurora Universalis on Mars. This is because Mars does not direct the energetic particles from the sun to its poles since it lacks an internal magnetic field. Today, researchers utilizing the MAVEN (Mars Atmosphere and Volatile Evolution) spacecraft find evidence for an aurora that may potentially cover the whole nightside of the planet. Venus lacks a magnetic field, thus it would not experience the same kind of nighttime aurora that we do.
To know more about aurora borealis go here:-
brainly.com/question/12757223
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- Magnitude: 12.1 N.
- Direction: 17.0° to the 8 N force.
<h3>Explanation</h3>
Refer to the diagram attached (created with GeoGebra). Consider the 5 N force in two directions: parallel to the 8 N force and normal to the 8 N force.
.
.
The sum of forces on each direction will be the resultant force on that direction:
- Resultant force parallel to the 8 N force:
. - Resultant force normal to the 8 N force:
.
Apply the Pythagorean Theorem to find the magnitude of the resultant force.
(3 sig. fig.).
The size of the angle between the resultant force and the 8 N force can be found from the tangent value of the angle. Tangent of the angle:
.
Find the size of the angle using inverse tangent:
.
In other words, the resultant force is 17.0° relative to the 8 N force.
