Answer:
Tension= 475N
Force= 225N
Explanation:
The question is not complete, here is the complete question
Also, see attached a free body diagram for your reference
<em>"A 20.0-kg uniform plank is supported by the floor at one end by a vertical rope at the other as shown in the figure. A 50.0-kg mass person stands on the plank a distance three-fourths of the length plank from the end on the floor.
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<em>a. What is the tension in the rope?
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<em>b. What is the magnitude of the force that the floor exerts on the plank?"</em>
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given data
mass of man=50kg
mass of plank=20kg
length of plank=10m
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let us make the lenght of the rope be d
The torque about the floor
That is taking moment about the floor
![N*0+T*d=20*10*d/2 + 50*10*3d/4\\\\T=100+375=475N\\\\](https://tex.z-dn.net/?f=N%2A0%2BT%2Ad%3D20%2A10%2Ad%2F2%20%2B%2050%2A10%2A3d%2F4%5C%5C%5C%5CT%3D100%2B375%3D475N%5C%5C%5C%5C)
Force will be also zero
![N+T=20*10+50*10\\\\N+T=700 \\\\N=700-475=225 newtons\\\\N+T=20*10+50*10\\\\N+T=700\\\\N=700-475=225newtons](https://tex.z-dn.net/?f=N%2BT%3D20%2A10%2B50%2A10%5C%5C%5C%5CN%2BT%3D700%20%5C%5C%5C%5CN%3D700-475%3D225%20newtons%5C%5C%5C%5CN%2BT%3D20%2A10%2B50%2A10%5C%5C%5C%5CN%2BT%3D700%5C%5C%5C%5CN%3D700-475%3D225newtons)
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Momentum of car
Given: Mass m= 1,400 Kg; V = 6.0 m/s
Formula: P = mv
P = (1,400 Kg)(6.0 m/s)
P = 8,400 Kg.m/s
Velocity of the rider to have the same momentum as a car.
Mass of rider and bicycle m = 100 Kg
P = mv
V = P/m
V = 8,400 Kg.m/s/100 Kg
V = 84 m/s
Answer:
A)
Explanation:
The lowest latitudes get the most energy from the sun. The highest latitudes get the least.
Answer:
0.4 N
Explanation:
The weight mg is 8 N, so the mass is:
mg = 8 N
m = 8 N / g
m = 8 N / (10 m/s²)
m = 0.8 kg
The force needed to accelerate it to 0.5 m/s².
F = ma
F = (0.8 kg) (0.5 m/s²)
F = 0.4 N