a...if you had the fully extended periodic table, these elements would be between La and Hf in period 6 and Ac and Rf in period 7
Answer: 31.8 g
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of
require 3 moles of
Thus 0.59 moles of
will require=
of
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent as it is present in more amount than required.
As 1 mole of
give = 2 moles of
Thus 0.59 moles of
give =
of
Mass of
Thus 31.8 g of
will be produced from the given masses of both reactants.
Answer:
.. / -.. --- -. - / -.- -. --- .-- / .-- .... .- - / .. / .-- .- ... / - .... .. -. -.- .. -. --. / .-.. . .- ...- .. -. --. / -- -.-- / -.-. .... --- .. .-.. -.. / -... . .... .. -. -.. / -. --- .-- / .. / ... ..- ..-. ..-. . .-. / .- / -.-. ..- .-. ... . / .- -. -.. / .. / .- -- / -... .-.. .. -. -.. / - .... .-. ..- / .- .-.. .-.. / - .... .. ... / .- -. --. . .-. / --. ..- .-.. - / ... .- -.. -. . ... ... / -.-. --- -- .. -. --. / - --- / .... .- ..- -. - / -- . / ..-. --- .-. . ...- . .-. / .. / -.-. .- -. - / .-- .- .. - / ..-. --- .-. / - .... . / -.-. .-.. .. ..-. ..-. / .- - / - .... . / . -. -.. / --- ..-. / - .... . / .-. .. ...- . .-. .-.-.- / .. ... / - .... .. ... / .-. . ...- . -. --. . / - .... .- - / .. -- / ... . . -.- .. -. --. ..--.. / --- .-. / ... . . -.- .. -. --. / ... --- -- --- -. . / - --- / .- ...- . -. --. . / -- . ..--.. / ... - ..- -.-. -.- / .. -. / -- -.-- / --- .-- -. / .--. .- .-. .- -.. --- -..- / .. / .-- .- -. .- / ... . - / -- -.-- / ... . .-.. ..-. / ..-. .-. . . .-.-.-
Explanation:
Answer:
110 degree
Explanation:
This is because Hybridization of an s orbital with all three p orbitals (px , py, and pz) results in four sp3 hybrid orbitals. sp3 hybrid orbitals are oriented at bond angle of 109.5 degrees from each other. This 109.5 degrees gives an arrangement of tetrahedral geometry
<u>Answer:</u>
<u>For A:</u> The
for the given reaction is 
<u>For B:</u> The
for the given reaction is 1642.
<u>Explanation:</u>
The given chemical reaction follows:

The expression of
for the above reaction follows:

We are given:

Putting values in above equation, we get:

Hence, the
for the given reaction is 
Relation of
with
is given by the formula:

where,
= equilibrium constant in terms of partial pressure = 
= equilibrium constant in terms of concentration = ?
R = Gas constant = 
T = temperature = 500 K
= change in number of moles of gas particles = 
Putting values in above equation, we get:

Hence, the
for the given reaction is 1642.