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2 years ago

When an acid reacts with a base what compounds are formed

1 answer:

6 0

When an acid and a base are placed together, they react to neutralize the acid and base properties and that produces salt.

Hope it helps :)

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Someone pls help me I will make you brain

wlad13 [49]

Answer:

It is true answer. Ozone = O3

7 0

3 years ago

What are the balanced chemical equations for Hydrochloric acid and potassium hydroxide?

-Dominant- [34]

HCl(aq) + KOH(s) --> KCl(aq) + H2O(l)

7 0

3 years ago

A container holds 6.4 moles of gas. Hydrogen gas makes up 25% of the total moles in the container. If the total pressure is 1.24

Degger [83]

The partial pressure of hydrogen is 0.31 atm

calculation

find the number of hydrogen moles the container, that is

25/100 x 6.4 =1.6 moles of hydrogen

find the partial pressure for hydrogen in 1.6 moles

that is 6.4 moles= 1.24 atm
1.6 moles= ?

by cross multiplication

1.6moles x1.24 atm/ 6.4 moles= 0.31 atm

6 0

3 years ago

When the temperature of the air is 25°C, the velocity of a sound wave traveling through the air is approximately

Vitek1552 [10]

Answer ; The correct answer is : 346 m/s .

Sound is a type of longitudinal wave , which is produced when a matter compress or refracts .

Speed of sounds depends on factors like medium , density , temperature etc .

Effect of Temperature on speed of sounds :

When the temperature increases , molecules gains energy and they starts vibrating and with higher temperature vibration becomes fast . So the waves of sounds can travel faster due to faster vibrations . Hence , speed of sounds is directly proportional to the temperature or speed of sounds increases with increase in temperature .

The speed of sounds at 0⁰C is 331 $\frac{m}{s}$

The relation between speed of sound and temperature is given as :

$V = 331 \frac{m}{s} + ( 0.6 \frac{m}{s- ^0C} * T )$

Given : Temperature = 25 ⁰ C

Plugging values in formula =>

$V = 331 \frac{m}{s} + (0.6 \frac{m}{s-^0C} * 25^0C)$

$V = 331 \frac{m}{s} + 15 \frac{m}{s}$

$V = 346 \frac{m}{s}$

7 0

3 years ago

Given the following data: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39

nalin [4]

Answer:

ΔH° = -11 kj

Explanation:

Step 1: Data given

1) Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ

2) 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39 kJ

3) Fe3O4(s) + CO(g) → 3 FeO(s) + CO2(g) ΔH = +18 kJ

Step 2: The balanced equation

FeO + CO → Fe + CO2

Step 3: Calculate ΔH for the reaction FeO(s) + CO(g) → Fe(s) + CO2(g).

To get this equation, we need to combine the 3 equations

We have to multiply the third equation by 2.

2Fe3O4(s) + 2CO(g) → 6 FeO(s) + 2CO2(g) ΔH = +54 kJ

This equation we add to the second equation

3Fe2O3(s) + CO(g) + 2Fe3O4(s) + 2CO(g) → 2Fe3O4(s) + CO2(g) + 6FeO(s) + 2CO2 (g)

3Fe2O3(s) + 3CO(g) → 3CO2(g) + 6FeO(s)

ΔH° = 2*18 + (-39) = 36 - 39 = -3 kJ

This new equation we will divide by 3

3Fe2O3(s) + 3CO(g) → 3CO2(g) + 6FeO(s)

Fe2O3(s) + CO(g) → CO2(g) + 2FeO(s)

ΔH° =-3/3 = -1 kJ

Now we will substract this new equation from the first equation

Fe2O3(s) + 3CO(g) - Fe2O3(s) - CO(g) → 2Fe(s) + 3CO2(g) -2FeO(s) - CO2(g)

2CO(g) + 2FeO(s) → 2Fe(s) + 2CO2(g)

ΔH° = -23kJ +1kJ

ΔH° = -22 kj

The next equation we will divide by 2

2CO(g) + 2FeO(s) → 2Fe(s) + 2CO2(g)

CO(g) + FeO(s) → Fe(s) + CO2(g)

ΔH° = -22kJ /2

ΔH° = -11 kj

7 0

3 years ago