Answer:
1-bromobutane, unlike others, will not be removed because it is an <em>alkane</em> and inert to concentrated sulfuric acid.
Explanation:
<em>Alkanes</em> are saturated organic compounds, primarily made up of hydrogen and carbon atoms. Saturation implies that they posses no double or triple bonds, therefore making them stable and unresponsive to addition reactions and also, concentrated sulfuric acid.
1-Butanol is a primary alcohol. Primary alcohols will react with acids to produce alkyl halides. 1-butene, as an alkene, will react with concentrated sulfuric acid to produce alkyl hyrgensulfate, while di-n-butyl will produce an ether when it reacts with concentrated sulfuric acid.
Therefore, these organic compounds will be washed and converted to other compounds by concentrated sulfuric acid except 1-bromobutane.
Distillation is a widely used method for separating mixtures based on differences in the conditions required to change the phase of components of the mixture. To separate a mixture of liquids, the liquid can be heated to force components, which have different boiling points , into the gas phase .
E ground pushes you forward. But that interaction is friction. Reduce friction and it doesn't matter how strong your legs are, the surface is incapable of pushing you accordingly. The coefficient of static friction is very low so it is easy to slide your foot rather than push.
Answer:
The FALSE statement is: It requires CO2.
Explanation:
Photophosphorylation is a process during which solar energy, in the form of a proton, impact on chlorophyll, exciting one electron. The excited electron pass along different carriers (Ferredoxin, cytochrome b6f and Plastocyanin) and eventually return to its origin. This electron passage promotes the formation of ATP from ADP (one molecule ATP is formed when three electrons pass throug the cycle).
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
When the the concentrations of both buffer components (the weak acid and its conjugate base) are equal:
[base] = [acid]
So, pH=pKa+log1 = pKa
<u>pH is equal to pKa of weak acid of buffer system
.</u>
When buffer contains more of weak acid than conjugate base:
[base] < [acid]
log [base]/[acid] = Negative,
So,
<u>When more of acid component is present, the pH is more acidic. (It decreases)</u>
When buffer contains more of conjugate base than weak acid:
[base] > [acid]
log [base]/[acid] = Positive,
So,
<u>When more of acid component is present, the pH is more acidic. (It increases)</u>
