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mrs_skeptik [129]
3 years ago
10

Name the following compound: HNO3

Chemistry
1 answer:
galben [10]3 years ago
5 0
Im pretty sure it nitric acid
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In the reaction n2 + 3h2 ---> 2nh3, how many grams of nh3 are produced if 25.0 g n2 reacts with excess h2? question 10 option
Lisa [10]
Molar mass of N2 = 28

Moles of N2 = 25 / 28 = 0.89

So, moles of NH3 produce = 2 x 0.89 = 1.78 

Note: H2 is in excess. so no need to care about it. 
8 0
3 years ago
Whether or not the process is observed in nature, which of the following could account for the transformation of gallium-67 to z
Sonja [21]

Answer:

Option a: positron emission.

Explanation:

In the transformation we have:

⁶⁷Ga  →  ⁶⁷Zn  

The reaction is:

^{67}_{Z}X \rightarrow ^{67}_{Z -1}Y

For Ga to become Zn, the atom nucleus has to lose a proton, so in the given options, the reaction that involves the transformation of a proton is the option a, positron emission.

In a positron emission, a proton becomes into a neutron and a positron:

^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y + ^{0}_{+1}e

Therefore, the correct answer is option a: positron emission.

I hope it helps you!

7 0
2 years ago
3. How would you expect the density of the gummy bear to change if you soaked it in isopropanol (rubbing alcohol, density
77julia77 [94]

Change occurs in the density of the gummy bear to change if we soaked it in isopropanol.

<h3>Effects on density by soaking isopropanol</h3>

We expect the density of the gummy bear to change if we soaked it in isopropanol because the gummy bear absorb the liquid which increase its density due to increasing weight of the gummy bear.

If a substance gains weight then its density also increases and we know that when the gummy bear was soaked in the isopropanol then its weight increases so its density is also changes so we can conclude that change occurs in the density of the gummy bear to change if we soaked it in isopropanol.

Learn more about density here: brainly.com/question/1354972

7 0
2 years ago
What is the value of work done on an object when a 50–newton force moves it 15 meters in the same direction as the force?
victus00 [196]

Answer:

work done = 750 J

Explanation:

Given data:

Force on object = 50 N

Distance covered = 15 m

Work done = ?

Solution:

W = F. d

W = work done

F = force

d = distance

Now we will put the values in formula.

W = 50 N × 15 m

W = 750 N. m = 750 J

7 0
3 years ago
______________________ produce evidence that helps to answer important questions or could also lead to new questions. A.investig
siniylev [52]

Answer:

B

Explanation:

6 0
3 years ago
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