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djyliett [7]
3 years ago
12

How are electromagnets made and how do they work?

Physics
1 answer:
frez [133]3 years ago
8 0
Electromagnets

When an electric current flows in a wire, it creates a magnetic field around the wire. This effect can be used to make an electromagnet. A simple electromagnet comprises a length of wire turned into a coil and connected to a battery or power supply.
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During destructive interference, two waves moving through the same medium will
ddd [48]
They will amplify eachother.
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2 years ago
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A mass on a spring vibrates in simple harmonic motion at an amplitude of 8.0 cm. If the mass of the object is 0.20 kg and the sp
Dmitry [639]

Answer:

Frequency, f = 3.73Hz

Explanation:

The frequency of a simple harmonic 6is given by:

f = w/2pi

But w= Sqrt( k/m)

Where k is the spring constant

And m is the mass

Given:

Mass=0.20kg

Spring constant, k=130N/m

w= Sqrt(130/0.20)

w= Sqrt(650)

w= 25.50 m

Frequency, f = w/2pi

f = 25.50/(2×3.142)

f = 3.73Hz

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3 years ago
Science: Could a dysfunction or disease of the nervous system affect other body systems, such as the muscular or digestive syste
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Answer:

You may experience the sudden onset of one or more symptoms, such as: Numbness, tingling, weakness, or inability to move a part or all of one side of the body (paralysis). Dimness, blurring, double vision, or loss of vision in one or both eyes. Loss of speech, trouble talking, or trouble understanding speech.

Request: Please mark me as the brainliest.

3 0
2 years ago
Suppose a photon with an energy of 1.60 eV strikes a piece of metal. If the electron that it hits loses 0.800 eV leaving the met
JulsSmile [24]

To solve this problem it is necessary to apply the concepts related to the change of Energy in photons and the conservation of energy.

From the theory we could consider that the energy change is subject to

\Delta E = E_0 -W_f

Where

E_0 =Initial Energy

W_f = Energy loses

Replacing we have that

\Delta E = 1.6-0.8

\Delta E = 0.8eV

Therefore the Kinetic energy of the electron once it has broken free of the metal surface is 0.8eV

7 0
2 years ago
If Superman really had x-ray vision at 0.12 nm wavelength and a 4.1 mm pupil diameter, at what maximum altitude could he disting
iVinArrow [24]

Answer:

Maximum altitude to see(L) =  1.47 × 10⁶ m (Approx)

Explanation:

Given:

wavelength (λ) = 0.12 nm = 0.12 × 10⁻⁹ m

Pupil Diameter (d) = 4.1 mm = 4 × 10⁻³ m

Separation distance (D) = 5.4 cm = 0.054 m

Find:

Maximum altitude to see(L)

Computation:

Resolving power = 1.22(λ / d)

D / L = 1.22(λ / d)

0.054 / L = 1.22 [(0.12 × 10⁻⁹) / (4 × 10⁻³ m)]

0.054 / L = 1.22 [0.03 × 10⁻⁶]

L = 0.054 / 1.22 [0.03 × 10⁻⁶]

L = 0.054 / [0.0366 × 10⁻⁶]

L = 1.47 × 10⁶

Maximum altitude to see(L) =  1.47 × 10⁶ m (Approx)

8 0
2 years ago
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