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Burka [1]
3 years ago
14

A wall clock has a second hand 22.0 cmcm long. For related problem-solving tips and strategies, you may want to view a Video Tut

or Solution of Fast car, flat curve. Part A What is the radial acceleration of the tip of this hand
Physics
1 answer:
olga55 [171]3 years ago
8 0

Answer:

Explanation:

The tip of the second hand moves on a circular path having radius equal to .22 m . Redial acceleration is given by the expression

ω²R where ω is angular velocity and R is radius of the circular path .

angular velocity of second hand = 2π / T where T is time period of circular motion . For second hand it is 60 s.

ω = 2π / T

= 2π / 60

= .1047

angular acceleration =  .1047² x .22

= 2.41 x 10⁻³ rad / s² .

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_________ = voltage / resistance <br> a. power <br> b. energy <br> c. charge <br> d. current
Fittoniya [83]

c.charge due to the reaction process between the two



4 0
3 years ago
Name the fundamental units involved in pascal<br>​
gtnhenbr [62]

Explanation:

Hey there!

Here,

Pascal is a unit of pressure.

pressure =  \frac{f}{a}

Now, As per the formula the units are:

kg, m and s^2.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
4 years ago
Which statement is true if the refractive index of medium A is greater than that of medium B?
allsm [11]

Answer:

I think it is C

Explanation:

7 0
3 years ago
A projectile is fired directly upwards at 49.4 m/s. A second projectile is dropped from rest at some higher elevation at the ins
8090 [49]

Answer:

Explanation:

velocity of first projectile after 3 s

v = u - gt

v = 49.4 - 9.8 x 3

= 20 m /s

Velocity of second projectile after 3 s after being dropped from rest

v = u + gt

= 0 + 9.8 x 3

= 29.4 m /s

They will be moving in opposite direction at the time of meeting , so their relative velocity

= 20 + 29.4 = 49.4 m /s

From the frame of reference of the first projectile, the velocity of the second projectile will be 49.4 m /s .

8 0
3 years ago
A rope breaks when the tension reaches 205 N. What is the maximum speed at which it can swing a 0.477 kg mass in a circle of rad
jekas [21]

Answer:

Maximum velocity will be 17.651 m /sec

Explanation:

We have given a rope breaks when tension reaches 205 N

Mass m = 0.477 kg

Radius of the circle r = 0.725 m

Tension in the rope is given by

T=\frac{mv^2}{r}

205=\frac{0.477\times v^2}{0.725}

0.477v^2=148.625

v^2=311.5828

v = 17.651 m /sec

8 0
4 years ago
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