I don’t know if i’m right but i think iconic solid .
The light bulbs ave to be a part of the loop in order for it to be successful because it have to have wires to a circuit breaker so you can see.
Answer:
There is 26.58 grams of gold formed
Explanation:
Step 1: Data given
17.6 A of current are passed through a gold solution for 37.0 min
Molar mass of Au = 196.967 g/mol
Step 2: The equation
Au^3+ + 3e- → Au
Step 3: Calculate coulombs
17.6 Coulomb/s * 37.0 min * 60 sec/min = 39072 Coulombs
1 Faraday = 96500 Coulombs
Step 4: Calculate faraday
39072 Coulombs / 96500 Coulombs / Faraday = 0.40489 Faraday
Step 5: Calculate mass of gold formed
For every 3 Faraday of electricity used up , 1 mole Au is formed
0.40489 Faraday * 1 mole Au/ 3 Faraday = 0.13496 mole Au
196.967 g/mol * 0.13496 mol = 26.58 g Au
There is 26.58 grams of gold formed
Answer:
Since two extra electrons are added, it is denoted by O2- hence it's an ion.
Answer:
cant read the questions...
Explanation: